Guava IntMath类的方法pow(int b,int k)将b返回到第k次幂。即使结果溢出,也将等于BigInteger.valueOf(b).pow(k).intValue()。此实现在O(log k)时间中运行。
用法:
public static int pow(int b, int k)
异常:如果k <0,则方法pow(int b,int k)抛出IllegalArgumentException。
范例1:
// Java code to show implementation of
// pow(int b, int k) method of Guava's
// IntMath class
import java.math.RoundingMode;
import com.google.common.math.IntMath;
class GFG {
static int findPow(int b, int k)
{
// Using pow(int b, int k)
// method of Guava's IntMath class
int ans = IntMath.pow(b, k);
// Return the answer
return ans;
}
// Driver code
public static void main(String args[])
{
int b = 4;
int k = 5;
int ans = findPow(b, k);
System.out.println(b + " to the " + k
+ "th power is:"
+ ans);
b = 12;
k = 3;
ans = findPow(b, k);
System.out.println(b + " to the " + k
+ "th power is:"
+ ans);
}
}
输出:
4 to the 5th power is:1024 12 to the 3th power is:1728
范例2:
// Java code to show implementation of
// pow(int b, int k) method of Guava's
// IntMath class
import java.math.RoundingMode;
import com.google.common.math.IntMath;
class GFG {
static int findPow(int b, int k)
{
try {
// Using pow(int b, int k)
// method of Guava's IntMath class
// This should throw "IllegalArgumentException"
// as k < 0
int ans = IntMath.pow(b, k);
// Return the answer
return ans;
}
catch (Exception e) {
System.out.println(e);
return -1;
}
}
// Driver code
public static void main(String args[])
{
int b = 4;
int k = -5;
try {
// Using pow(int b, int k)
// method of Guava's IntMath class
// This should throw "IllegalArgumentException"
// as k < 0
IntMath.pow(b, k);
}
catch (Exception e) {
System.out.println(e);
}
}
}
输出:
java.lang.IllegalArgumentException:exponent (-5) must be >= 0
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注:本文由纯净天空筛选整理自bansal_rtk_大神的英文原创作品 Java Guava | pow(int b, int k) method of IntMath Class。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。