C++ iswpunct()用法及代码示例

iswpunct()是C /C++中的一个函数，用于测试宽字符代码是否表示程序当前语言环境中的punct类字符。如果Wide-Character是标点符号宽字符代码，则返回非零值，否则应返回0。此函数在cwctype头文件中定义。该函数检查ch是否为标点字符。标点字符为跟随

! " # $ % & ' () * +, - . / : ;  ? @ [\] ^ _ ` {|} ~

用法:

int iswpunct(ch)

参数：该函数接受单个强制参数ch，该参数指定要检查的字符。

返回值：如果字符ch是标点字符，则该函数返回非零值，否则返回零。

以下示例程序旨在说明上述函数：

// C++ program to illustrate 
// the iswpunct() function 
#include <bits/stdc++.h> 
int main() 
{ 
    int i = 0; 
    int count_ = 0; 
  
    // string declaration 
    char string1[] = "~Hello geekforgeeks !"; 
    char string2[count_]; 
  
    // iterate in the string 
    while (string1[i]) { 
  
        // check if the character is 
        // punctuation mark or not 
        if (iswpunct(string1[i])) { 
  
            // store the punctuation characters 
            string2[count_] = string1[i]; 
            count_++; 
        } 
        i++; 
    } 
    // prints the punctuation character 
    printf("The sentence contains %d punct. character :\n", count_); 
    for (int i = 0; i < count_; i++) 
        printf("%c ", string2[i]); 
    return 0; 
}

输出：

The sentence contains 2 punct. character :
~ !

程序2:

// C++ program to illustrate 
// the iswpunct() function 
#include <bits/stdc++.h> 
int main() 
{ 
    int i = 0; 
    int count_ = 0; 
  
    // string declaration 
    char string1[] = "@#$^gfg"; 
    char string2[count_]; 
  
    // iterate in the string 
    while (string1[i]) { 
  
        // check if the character is 
        // punctuation mark or not 
        if (iswpunct(string1[i])) { 
  
            // store the punctuation characters 
            string2[count_] = string1[i]; 
            count_++; 
        } 
        i++; 
    } 
    // prints the punctuation character 
    printf("The sentence contains %d punct. character :\n", count_); 
    for (int i = 0; i < count_; i++) 
        printf("%c ", string2[i]); 
    return 0; 
}

输出：

The sentence contains 4 punct. character :
@ # $ ^

相关用法

注：本文由纯净天空筛选整理自AmanSrivastava1大神的英文原创作品 iswpunct() function in C/C++。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。