C++ iswpunct()用法及代碼示例

iswpunct()是C /C++中的一個函數，用於測試寬字符代碼是否表示程序當前語言環境中的punct類字符。如果Wide-Character是標點符號寬字符代碼，則返回非零值，否則應返回0。此函數在cwctype頭文件中定義。該函數檢查ch是否為標點字符。標點字符為跟隨

! " # $ % & ' () * +, - . / : ;  ? @ [\] ^ _ ` {|} ~

用法:

int iswpunct(ch)

參數：該函數接受單個強製參數ch，該參數指定要檢查的字符。

返回值：如果字符ch是標點字符，則該函數返回非零值，否則返回零。

以下示例程序旨在說明上述函數：

// C++ program to illustrate 
// the iswpunct() function 
#include <bits/stdc++.h> 
int main() 
{ 
    int i = 0; 
    int count_ = 0; 
  
    // string declaration 
    char string1[] = "~Hello geekforgeeks !"; 
    char string2[count_]; 
  
    // iterate in the string 
    while (string1[i]) { 
  
        // check if the character is 
        // punctuation mark or not 
        if (iswpunct(string1[i])) { 
  
            // store the punctuation characters 
            string2[count_] = string1[i]; 
            count_++; 
        } 
        i++; 
    } 
    // prints the punctuation character 
    printf("The sentence contains %d punct. character :\n", count_); 
    for (int i = 0; i < count_; i++) 
        printf("%c ", string2[i]); 
    return 0; 
}

輸出：

The sentence contains 2 punct. character :
~ !

程序2:

// C++ program to illustrate 
// the iswpunct() function 
#include <bits/stdc++.h> 
int main() 
{ 
    int i = 0; 
    int count_ = 0; 
  
    // string declaration 
    char string1[] = "@#$^gfg"; 
    char string2[count_]; 
  
    // iterate in the string 
    while (string1[i]) { 
  
        // check if the character is 
        // punctuation mark or not 
        if (iswpunct(string1[i])) { 
  
            // store the punctuation characters 
            string2[count_] = string1[i]; 
            count_++; 
        } 
        i++; 
    } 
    // prints the punctuation character 
    printf("The sentence contains %d punct. character :\n", count_); 
    for (int i = 0; i < count_; i++) 
        printf("%c ", string2[i]); 
    return 0; 
}

輸出：

The sentence contains 4 punct. character :
@ # $ ^

相關用法

注：本文由純淨天空篩選整理自AmanSrivastava1大神的英文原創作品 iswpunct() function in C/C++。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。