库“boost/lexical_cast.hpp”中定义的Boost.LexicalCast提供了强制转换运算符boost::lexical_cast，可以将数字从字符串转换为数字类型，如int或double，反之亦然。
boost::lexical_cast是std::stoi(，std::stod(和std::to_string()等函数的替代方法，它们已添加到C++ 11中的标准库中。现在让我们在程序中查看此函数的实现。例子：
Conversion integer -> string string- > integer integer -> char float- > string
关联的异常：如果转换失败，则引发从bad_cast派生的bad_lexical_cast类型的异常。引发异常是因为浮点数52.50和字符串“GeeksforGeeks”无法转换为int类型的数字。
// CPP program to illustrate
// Boost.Lexical_Cast in C++
#include "boost/lexical_cast.hpp"
#include <bits/stdc++.h>
using namespace std;
using boost::lexical_cast;
using boost::bad_lexical_cast;
int main() {
// integer to string conversion
int s = 23;
string s1 = lexical_cast<string>(s);
cout << s1 << endl;
// integer to char conversion
array<char, 64> msg = lexical_cast<array<char, 64>>(45);
cout << msg[0] << msg[1] << endl;
// string to integer conversion in integer value
int num = lexical_cast<int>("1234");
cout << num << endl;
// bad conversion float to int
// using try and catch we display the error
try {
int num2 = lexical_cast<int>("52.20");
}
// To catch exception
catch (bad_lexical_cast &e) {
cout << "Exception caught:" << e.what() << endl;
}
// bad conversion string to integer character
// using tru and catch we display the error
try {
int i = lexical_cast<int>("GeeksforGeeks");
}
// catching Exception
catch (bad_lexical_cast &e) {
cout << "Exception caught:" << e.what() << endl;
}
return 0;
}输出：-
23 45 1234 Exception caught:bad lexical cast:source type value could not be interpreted as target Exception caught:bad lexical cast:source type value could not be interpreted as target
参考：-http://www.boost.org/
注：本文由纯净天空筛选整理自ajay0007大神的英文原创作品 Boost.Lexical_Cast in C++。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。