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C++ Boost.Lexical_Cast用法及代碼示例


庫“boost/lexical_cast.hpp”中定義的Boost.LexicalCast提供了強製轉換運算符boost::lexical_cast,可以將數字從字符串轉換為數字類型,如int或double,反之亦然。

boost::lexical_cast是std::stoi(,std::stod(和std::to_string()等函數的替代方法,它們已添加到C++ 11中的標準庫中。現在讓我們在程序中查看此函數的實現。例子:

Conversion
integer -> string
string- > integer
integer -> char
float- > string

關聯的異常:如果轉換失敗,則引發從bad_cast派生的bad_lexical_cast類型的異常。引發異常是因為浮點數52.50和字符串“GeeksforGeeks”無法轉換為int類型的數字。


// CPP program to illustrate 
// Boost.Lexical_Cast in C++ 
#include "boost/lexical_cast.hpp" 
#include <bits/stdc++.h> 
using namespace std; 
using boost::lexical_cast; 
using boost::bad_lexical_cast; 
int main() { 
  
  // integer to string conversion 
  int s = 23; 
  string s1 = lexical_cast<string>(s); 
  cout << s1 << endl; 
  
  // integer to char conversion 
  array<char, 64> msg = lexical_cast<array<char, 64>>(45); 
  cout << msg[0] << msg[1] << endl; 
  
  // string to integer conversion in integer value 
  int num = lexical_cast<int>("1234"); 
  cout << num << endl; 
  
  // bad conversion float to int 
  // using try and catch we display the error 
  try { 
    int num2 = lexical_cast<int>("52.20"); 
  } 
  
  // To catch exception 
  catch (bad_lexical_cast &e) { 
    cout << "Exception caught:" << e.what() << endl; 
  } 
  
  // bad conversion string to integer character 
  // using tru and catch we display the error 
  try { 
    int i = lexical_cast<int>("GeeksforGeeks"); 
  } 
  
  // catching Exception 
  catch (bad_lexical_cast &e) { 
    cout << "Exception caught:" << e.what() << endl; 
  } 
  
  return 0; 
}

輸出:-

23
45
1234
Exception caught:bad lexical cast:source type value could not be interpreted as target
Exception caught:bad lexical cast:source type value could not be interpreted as target

參考:-http://www.boost.org/




注:本文由純淨天空篩選整理自ajay0007大神的英文原創作品 Boost.Lexical_Cast in C++。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。