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C++ bitset all()用法及代码示例


bitset::all()是C++ STL中的内置函数,如果在位的二进制表示中初始化了所有位,则该值返回True。如果未设置所有位,则返回False。

用法:

bool bitset_name.all() 

参数:该函数不接受任何参数。


返回值:该函数返回一个布尔值。如果所有位均已设置,则返回的布尔值为true,否则返回值为false,

下面的程序演示了bitset::all()函数。

示例1:

// CPP program to illustrate the 
// bitset::all() function 
#include <bits/stdc++.h> 
using namespace std; 
  
int main() 
{ 
    // Initialization of bitset 
    bitset<4> b1(string("1100")); 
    bitset<6> b2(string("111111")); 
  
    // Function that checks if all 
    // the bits are set or not 
    bool result1 = b1.all(); 
    if (result1) 
        cout << b1 << " has all bits set"
             << endl; 
    else
        cout << b1 << " does not have all bits set"
             << endl; 
  
    // Function that checks if all 
    // the bits are set or not 
    bool result2 = b2.all(); 
    if (result2) 
        cout << b2 << " has all bits set"
             << endl; 
    else
        cout << b2 << " does not have all bits set"
             << endl; 
  
    return 0; 
}
输出:
1100 does not have all bits set
111111 has all bits set

示例2:

// CPP program to illustrate the 
// bitset::all() function 
// when the input is as a number 
  
#include <bits/stdc++.h> 
using namespace std; 
  
int main() 
{ 
    // Initialization of bitset 
    bitset<2> b1(3); 
    bitset<3> b2(5); 
  
    // Function that checks if all 
    // the bits are set or not 
    bool result1 = b1.all(); 
    if (result1) 
        cout << b1 << " has all bits set"
             << endl; 
    else
        cout << b1 << " does not have all bits set"
             << endl; 
  
    // Function that checks if all 
    // the bits are set or not 
    bool result2 = b2.all(); 
    if (result2) 
        cout << b2 << " has all bits set"
             << endl; 
    else
        cout << b2 << " does not have all bits set"
             << endl; 
  
    return 0; 
}
输出:
11 has all bits set
101 does not have all bits set


相关用法


注:本文由纯净天空筛选整理自gopaldave大神的英文原创作品 bitset all() function in C++ STL。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。