C++ bitset all()用法及代碼示例

bitset::all()是C++ STL中的內置函數，如果在位的二進製表示中初始化了所有位，則該值返回True。如果未設置所有位，則返回False。

用法:

bool bitset_name.all()

參數：該函數不接受任何參數。

返回值：該函數返回一個布爾值。如果所有位均已設置，則返回的布爾值為true，否則返回值為false，

下麵的程序演示了bitset::all()函數。

示例1:

// CPP program to illustrate the 
// bitset::all() function 
#include <bits/stdc++.h> 
using namespace std; 
  
int main() 
{ 
    // Initialization of bitset 
    bitset<4> b1(string("1100")); 
    bitset<6> b2(string("111111")); 
  
    // Function that checks if all 
    // the bits are set or not 
    bool result1 = b1.all(); 
    if (result1) 
        cout << b1 << " has all bits set"
             << endl; 
    else
        cout << b1 << " does not have all bits set"
             << endl; 
  
    // Function that checks if all 
    // the bits are set or not 
    bool result2 = b2.all(); 
    if (result2) 
        cout << b2 << " has all bits set"
             << endl; 
    else
        cout << b2 << " does not have all bits set"
             << endl; 
  
    return 0; 
}

輸出：

1100 does not have all bits set
111111 has all bits set

示例2:

// CPP program to illustrate the 
// bitset::all() function 
// when the input is as a number 
  
#include <bits/stdc++.h> 
using namespace std; 
  
int main() 
{ 
    // Initialization of bitset 
    bitset<2> b1(3); 
    bitset<3> b2(5); 
  
    // Function that checks if all 
    // the bits are set or not 
    bool result1 = b1.all(); 
    if (result1) 
        cout << b1 << " has all bits set"
             << endl; 
    else
        cout << b1 << " does not have all bits set"
             << endl; 
  
    // Function that checks if all 
    // the bits are set or not 
    bool result2 = b2.all(); 
    if (result2) 
        cout << b2 << " has all bits set"
             << endl; 
    else
        cout << b2 << " does not have all bits set"
             << endl; 
  
    return 0; 
}

輸出：

11 has all bits set
101 does not have all bits set

相關用法

注：本文由純淨天空篩選整理自gopaldave大神的英文原創作品 bitset all() function in C++ STL。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。