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VB.NET Tuple<T1,T2>.Item1属性代码示例

本文整理汇总了VB.NET中System.Tuple<T1,T2>.Item1属性的典型用法代码示例。如果您正苦于以下问题:VB.NET Tuple<T1,T2>.Item1属性的具体用法?VB.NET Tuple<T1,T2>.Item1怎么用?VB.NET Tuple<T1,T2>.Item1使用的例子?那么恭喜您, 这里精选的属性代码示例或许可以为您提供帮助。您也可以进一步了解该属性所在System.Tuple<T1,T2>的用法示例。

在下文中一共展示了Tuple<T1,T2>.Item1属性的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的VB.NET代码示例。

示例1: modMain

Module modMain
   Public Sub Main()
      Dim dividend, divisor As Integer
      Dim result As Tuple(Of Integer, Integer)
      
      dividend = 136945 : divisor = 178
      result = IntegerDivide(dividend, divisor)
      If result IsNot Nothing Then
         Console.WriteLine("{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2)
      Else
         Console.WriteLine("{0} \ {1} = <Error>", dividend, divisor)
      End If
                        
      dividend = Int32.MaxValue : divisor = -2073
      result = IntegerDivide(dividend, divisor)
      If result IsNot Nothing Then
         Console.WriteLine("{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2)
      Else
         Console.WriteLine("{0} \ {1} = <Error>", dividend, divisor)
      End If
   End Sub
   
   Private Function IntegerDivide(dividend As Integer, divisor As Integer) As Tuple(Of Integer, Integer)
      Try
         Dim remainder As Integer
         Dim quotient As Integer = Math.DivRem(dividend, divisor, remainder)
         Return New Tuple(Of Integer, Integer)(quotient, remainder)
      Catch e As DivideByZeroException
         Return Nothing
      End Try      
   End Function
End Module
开发者ID:VB.NET开发者,项目名称:System,代码行数:34,代码来源:Tuple.Item1

输出:

136945 \ 178 = 769, remainder 63
2147483647 \ -2073 = -1035930, remainder 757



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