本文整理汇总了Python中sympy.core.Basic.bernoulli方法的典型用法代码示例。如果您正苦于以下问题:Python Basic.bernoulli方法的具体用法?Python Basic.bernoulli怎么用?Python Basic.bernoulli使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sympy.core.Basic
的用法示例。
在下文中一共展示了Basic.bernoulli方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: _eval_apply
# 需要导入模块: from sympy.core import Basic [as 别名]
# 或者: from sympy.core.Basic import bernoulli [as 别名]
def _eval_apply(self, z, a=S.One):
z, a = map(Basic.sympify, (z, a))
if isinstance(a, Basic.Number):
if isinstance(a, Basic.NaN):
return S.NaN
elif isinstance(a, Basic.Zero):
return self(z)
if isinstance(z, Basic.Number):
if isinstance(z, Basic.NaN):
return S.NaN
elif isinstance(z, Basic.Infinity):
return S.One
elif isinstance(z, Basic.Zero):
if a.is_negative:
return S.Half - a - 1
else:
return S.Half - a
elif isinstance(z, Basic.One):
return S.ComplexInfinity
elif isinstance(z, Basic.Integer):
if isinstance(a, Basic.Integer):
if z.is_negative:
zeta = (-1)**z * Basic.bernoulli(-z+1)/(-z+1)
elif z.is_even:
B, F = Basic.bernoulli(z), Basic.Factorial(z)
zeta = 2**(z-1) * abs(B) * pi**z / F
if a.is_negative:
return zeta + Basic.harmonic(abs(a), z)
else:
return zeta - Basic.harmonic(a-1, z)