本文整理汇总了Python中sympy.combinatorics.permutations.Permutation.conjugate方法的典型用法代码示例。如果您正苦于以下问题：Python Permutation.conjugate方法的具体用法？Python Permutation.conjugate怎么用？Python Permutation.conjugate使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sympy.combinatorics.permutations.Permutation的用法示例。
在下文中一共展示了Permutation.conjugate方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_Permutation
# 需要导入模块: from sympy.combinatorics.permutations import Permutation [as 别名]
# 或者: from sympy.combinatorics.permutations.Permutation import conjugate [as 别名]
def test_Permutation():
p = Permutation([2, 5, 1, 6, 3, 0, 4])
q = Permutation([[1], [0, 3, 5, 6, 2, 4]])
assert Permutation(p.cyclic_form).array_form == p.array_form
assert p.cardinality == 5040
assert q.cardinality == 5040
assert q.cycles == 2
assert q*p == Permutation([4, 6, 1, 2, 5, 3, 0])
assert p*q == Permutation([6, 5, 3, 0, 2, 4, 1])
assert perm_af_mul([2, 5, 1, 6, 3, 0, 4], [3, 1, 4, 5, 0, 6, 2]) == \
[6, 5, 3, 0, 2, 4, 1]
assert cyclic([(2,3,5)], 5) == [[1, 2, 4], [0], [3]]
assert (Permutation([[1,2,3],[0,4]])*Permutation([[1,2,4],[0],[3]])).cyclic_form == \
[[1, 3], [0, 4, 2]]
assert q.array_form == [3, 1, 4, 5, 0, 6, 2]
assert p.cyclic_form == [[3, 6, 4], [0, 2, 1, 5]]
assert p.transpositions() == [(3, 4), (3, 6), (0, 5), (0, 1), (0, 2)]
assert p**13 == p
assert q**2 == Permutation([5, 1, 0, 6, 3, 2, 4])
assert p+q == Permutation([5, 6, 3, 1, 2, 4, 0])
assert q+p == p+q
assert p-q == Permutation([6, 3, 5, 1, 2, 4, 0])
assert q-p == Permutation([1, 4, 2, 6, 5, 3, 0])
a = p-q
b = q-p
assert (a+b).is_Identity
assert p.conjugate(q) == Permutation([5, 3, 0, 4, 6, 2, 1])
assert p.conjugate(q) == ~q*p*q == p**q
assert q.conjugate(p) == Permutation([6, 3, 2, 0, 1, 4, 5])
assert q.conjugate(p) == ~p*q*p == q**p
assert p.commutator(q) == Permutation([1, 4, 5, 6, 3, 0, 2])
assert q.commutator(p) == Permutation([5, 0, 6, 4, 1, 2, 3])
assert p.commutator(q) == ~ q.commutator(p)
assert len(p.atoms()) == 7
assert q.atoms() == set([0, 1, 2, 3, 4, 5, 6])
assert p.inversion_vector() == [2, 4, 1, 3, 1, 0]
assert q.inversion_vector() == [3, 1, 2, 2, 0, 1]
assert Permutation.from_inversion_vector(p.inversion_vector()) == p
assert Permutation.from_inversion_vector(q.inversion_vector()).array_form\
== q.array_form
assert Permutation([i for i in range(500,-1,-1)]).inversions() == 125250
assert Permutation([0, 4, 1, 3, 2]).parity() == 0
assert Permutation([0, 1, 4, 3, 2]).parity() == 1
assert perm_af_parity([0, 4, 1, 3, 2]) == 0
assert perm_af_parity([0, 1, 4, 3, 2]) == 1
s = Permutation([0])
assert s.is_Singleton
r = Permutation([3, 2, 1, 0])
assert (r**2).is_Identity
assert (p*(~p)).is_Identity
assert (~p)**13 == Permutation([5, 2, 0, 4, 6, 1, 3])
assert ~(r**2).is_Identity
assert p.max() == 6
assert p.min() == 0
q = Permutation([[6], [5], [0, 1, 2, 3, 4]])
assert q.max() == 4
assert q.min() == 0
p = Permutation([1, 5, 2, 0, 3, 6, 4])
q = Permutation([[1, 2, 3, 5, 6], [0, 4]])
assert p.ascents() == [0, 3, 4]
assert q.ascents() == [1, 2, 4]
assert r.ascents() == []
assert p.descents() == [1, 2, 5]
assert q.descents() == [0, 3, 5]
assert Permutation(r.descents()).is_Identity
assert p.inversions() == 7
assert p.signature() == -1
assert q.inversions() == 11
assert q.signature() == -1
assert (p*(~p)).inversions() == 0
assert (p*(~p)).signature() == 1
assert p.order() == 6
assert q.order() == 10
assert (p**(p.order())).is_Identity
assert p.length() == 6
assert q.length() == 7
#.........这里部分代码省略.........