本文整理汇总了Python中sympy.Interval.open方法的典型用法代码示例。如果您正苦于以下问题：Python Interval.open方法的具体用法？Python Interval.open怎么用？Python Interval.open使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sympy.Interval的用法示例。
在下文中一共展示了Interval.open方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_issue_10285
# 需要导入模块: from sympy import Interval [as 别名]
# 或者: from sympy.Interval import open [as 别名]
def test_issue_10285():
assert FiniteSet(-x - 1).intersect(Interval.Ropen(1, 2)) == FiniteSet(x).intersect(Interval.Lopen(-3, -2))
eq = -x - 2 * (-x - y)
s = signsimp(eq)
ivl = Interval.open(0, 1)
assert FiniteSet(eq).intersect(ivl) == FiniteSet(s).intersect(ivl)
assert FiniteSet(-eq).intersect(ivl) == FiniteSet(s).intersect(Interval.open(-1, 0))
eq -= 1
ivl = Interval.Lopen(1, oo)
assert FiniteSet(eq).intersect(ivl) == FiniteSet(s).intersect(Interval.Lopen(2, oo))示例2: test_reduce_rational_inequalities_real_relational
# 需要导入模块: from sympy import Interval [as 别名]
# 或者: from sympy.Interval import open [as 别名]
def test_reduce_rational_inequalities_real_relational():
assert reduce_rational_inequalities([], x) == False
assert reduce_rational_inequalities(
[[(x**2 + 3*x + 2)/(x**2 - 16) >= 0]], x, relational=False) == \
Union(Interval.open(-oo, -4), Interval(-2, -1), Interval.open(4, oo))
assert reduce_rational_inequalities(
[[((-2*x - 10)*(3 - x))/((x**2 + 5)*(x - 2)**2) < 0]], x,
relational=False) == \
Union(Interval.open(-5, 2), Interval.open(2, 3))
assert reduce_rational_inequalities([[(x + 1)/(x - 5) <= 0]], x,
relational=False) == \
Interval.Ropen(-1, 5)
assert reduce_rational_inequalities([[(x**2 + 4*x + 3)/(x - 1) > 0]], x,
relational=False) == \
Union(Interval.open(-3, -1), Interval.open(1, oo))
assert reduce_rational_inequalities([[(x**2 - 16)/(x - 1)**2 < 0]], x,
relational=False) == \
Union(Interval.open(-4, 1), Interval.open(1, 4))
assert reduce_rational_inequalities([[(3*x + 1)/(x + 4) >= 1]], x,
relational=False) == \
Union(Interval.open(-oo, -4), Interval.Ropen(S(3)/2, oo))
assert reduce_rational_inequalities([[(x - 8)/x <= 3 - x]], x,
relational=False) == \
Union(Interval.Lopen(-oo, -2), Interval.Lopen(0, 4))
# issue sympy/sympy#10237
assert reduce_rational_inequalities(
[[x < oo, x >= 0, -oo < x]], x, relational=False) == Interval(0, oo)示例3: test_solve_abs
# 需要导入模块: from sympy import Interval [as 别名]
# 或者: from sympy.Interval import open [as 别名]
def test_solve_abs():
assert solveset_real(Abs(x) - 2, x) == FiniteSet(-2, 2)
assert solveset_real(Abs(x + 3) - 2 * Abs(x - 3), x) == FiniteSet(1, 9)
assert solveset_real(2 * Abs(x) - Abs(x - 1), x) == FiniteSet(-1, Rational(1, 3))
assert solveset_real(Abs(x - 7) - 8, x) == FiniteSet(-S(1), S(15))
# issue 9565. Note: solveset_real does not solve this as it is
# solveset's job to handle Relationals
assert solveset(Abs((x - 1) / (x - 5)) <= S(1) / 3, domain=S.Reals) == Interval(-1, 2)
# issue #10069
eq = abs(1 / (x - 1)) - 1 > 0
u = Union(Interval.open(0, 1), Interval.open(1, 2))
assert solveset_real(eq, x) == u
assert solveset(eq, x, domain=S.Reals) == u
raises(ValueError, lambda: solveset(abs(x) - 1, x))示例4: test_solve_abs
# 需要导入模块: from sympy import Interval [as 别名]
# 或者: from sympy.Interval import open [as 别名]
def test_solve_abs():
assert solveset_real(Abs(x) - 2, x) == FiniteSet(-2, 2)
assert solveset_real(Abs(x + 3) - 2*Abs(x - 3), x) == \
FiniteSet(1, 9)
assert solveset_real(2*Abs(x) - Abs(x - 1), x) == \
FiniteSet(-1, Rational(1, 3))
assert solveset_real(Abs(x - 7) - 8, x) == FiniteSet(-S(1), S(15))
# issue 9565. Note: solveset_real does not solve this as it is
# solveset's job to handle Relationals
assert solveset(Abs((x - 1)/(x - 5)) <= S(1)/3, domain=S.Reals
) == Interval(-1, 2)
# issue #10069
assert solveset_real(abs(1/(x - 1)) - 1 > 0, x) == \
ConditionSet(x, Eq((1 - Abs(x - 1))/Abs(x - 1) > 0, 0),
S.Reals)
assert solveset(abs(1/(x - 1)) - 1 > 0, x, domain=S.Reals
) == Union(Interval.open(0, 1), Interval.open(1, 2))示例5: test_issue_8715
# 需要导入模块: from sympy import Interval [as 别名]
# 或者: from sympy.Interval import open [as 别名]
def test_issue_8715():
eq = x + 1 / x > -2 + 1 / x
assert solveset(eq, x, S.Reals) == (Interval.open(-2, oo) - FiniteSet(0))
assert solveset(eq.subs(x, log(x)), x, S.Reals) == Interval.open(exp(-2), oo) - FiniteSet(1)