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Python Solution.wordBreak方法代码示例

本文整理汇总了Python中solution.Solution.wordBreak方法的典型用法代码示例。如果您正苦于以下问题:Python Solution.wordBreak方法的具体用法?Python Solution.wordBreak怎么用?Python Solution.wordBreak使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在solution.Solution的用法示例。


在下文中一共展示了Solution.wordBreak方法的6个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_2

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import wordBreak [as 别名]
def test_2():
    sol = Solution()
    s = "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa" \
        "aaaaaaaaaaaaaaaaaaaaaaaaaaabaaaaaaaaaaaaaaaaaaaa" \
        "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
    d = ["a", "aa", "aaa", "aaaa", "aaaaa", "aaaaaa",
         "aaaaaaa", "aaaaaaaa", "aaaaaaaaa", "aaaaaaaaaa"]
    assert sol.wordBreak(s, d) == []
开发者ID:misaka-10032,项目名称:leetcode,代码行数:10,代码来源:test.py

示例2: test1

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import wordBreak [as 别名]
 def test1(self):
     s = Solution()
     input_str = 'a'
     input_dict = ['a']
     res = s.wordBreak(input_str, input_dict)
     print res
     s2 = Solution2()
     res = s2.wordBreak(input_str, input_dict)
     print res
开发者ID:johnnywsd,项目名称:leetcode_python,代码行数:11,代码来源:test.py

示例3: test2

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import wordBreak [as 别名]
 def test2(self):
     s = Solution()
     input_str = 'leetcode'
     input_dict = ['leet', 'code']
     res = s.wordBreak(input_str, input_dict)
     print res
     s2 = Solution2()
     res = s2.wordBreak(input_str, input_dict)
     print res
开发者ID:johnnywsd,项目名称:leetcode_python,代码行数:11,代码来源:test.py

示例4: test_0

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import wordBreak [as 别名]
def test_0():
    sol = Solution()
    assert sol.wordBreak('', [])
    assert sol.wordBreak('', ['a'])
    assert not sol.wordBreak('a', [])
    assert sol.wordBreak('a', ['a'])
    assert sol.wordBreak('abc', ['bc', 'abc'])
    assert not sol.wordBreak('abc', ['ac', 'bc'])
开发者ID:misaka-10032,项目名称:leetcode,代码行数:10,代码来源:test.py

示例5: set

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import wordBreak [as 别名]
#!/usr/bin/env python
# -*- coding: utf-8 -*-

from solution import Solution

s = "catsanddog"
wordDict = set(["cat", "cats", "and", "sand", "dog"])
sol = Solution()
res = sol.wordBreak(s, wordDict)
print(res)
开发者ID:zhlinh,项目名称:leetcode,代码行数:12,代码来源:test.py

示例6: test_1

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import wordBreak [as 别名]
def test_1():
    sol = Solution()
    s = 'catsanddog'
    d = ['cat', 'cats', 'and', 'sand', 'dog']
    tgt = ['cats and dog', 'cat sand dog']
    assert sorted(sol.wordBreak(s, d)) == sorted(tgt)
开发者ID:misaka-10032,项目名称:leetcode,代码行数:8,代码来源:test.py


注:本文中的solution.Solution.wordBreak方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。