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Python Solution.reverseBetween方法代码示例

本文整理汇总了Python中solution.Solution.reverseBetween方法的典型用法代码示例。如果您正苦于以下问题:Python Solution.reverseBetween方法的具体用法?Python Solution.reverseBetween怎么用?Python Solution.reverseBetween使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在solution.Solution的用法示例。


在下文中一共展示了Solution.reverseBetween方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test3

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import reverseBetween [as 别名]
 def test3(self):
     head = ListNode(1)
     s = Solution()
     res = s.reverseBetween(head, 1, 1)
     while res:
         print res.val
         res = res.next
开发者ID:johnnywsd,项目名称:leetcode_python,代码行数:9,代码来源:test.py

示例2: test2

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import reverseBetween [as 别名]
 def test2(self):
     head = ListNode(1)
     node2 = ListNode(2)
     head.next = node2
     s = Solution()
     res = s.reverseBetween(head, 1, 2)
     while res:
         print res.val
         res = res.next
开发者ID:johnnywsd,项目名称:leetcode_python,代码行数:11,代码来源:test.py

示例3: test1

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import reverseBetween [as 别名]
 def test1(self):
     head = ListNode(1)
     node2 = ListNode(2)
     node3 = ListNode(3)
     head.next = node2
     node2.next = node3
     s = Solution()
     res = s.reverseBetween(head, 1, 3)
     while res:
         print res.val
         res = res.next
开发者ID:johnnywsd,项目名称:leetcode_python,代码行数:13,代码来源:test.py

示例4: mkListNode

# 需要导入模块: from solution import Solution [as 别名]
# 或者: from solution.Solution import reverseBetween [as 别名]
from solution import ListNode

def mkListNode(nums):
    """
    :type: nums: List
    :rtype: ListNode
    """
    head = lnp = ListNode(0)
    for i in range(len(nums)):
        lnp.next = ListNode(nums[i])
        lnp = lnp.next
    return head.next

def lsListNode(head):
    """
    :type: head: ListNode
    :rtype: List
    """
    lnp = head
    rList = []
    while lnp != None:
        rList.append(lnp.val)
        lnp = lnp.next
    return rList

inpt = mkListNode([1, 2, 3, 4, 5])
m, n = 3, 4
sol = Solution()
res = sol.reverseBetween(inpt, m, n)
print(lsListNode(res))
开发者ID:zhlinh,项目名称:leetcode,代码行数:32,代码来源:test.py


注:本文中的solution.Solution.reverseBetween方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。