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Python QAction.setMenuRole方法代码示例

本文整理汇总了Python中qtpy.QtWidgets.QAction.setMenuRole方法的典型用法代码示例。如果您正苦于以下问题:Python QAction.setMenuRole方法的具体用法?Python QAction.setMenuRole怎么用?Python QAction.setMenuRole使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在qtpy.QtWidgets.QAction的用法示例。


在下文中一共展示了QAction.setMenuRole方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: create_action

# 需要导入模块: from qtpy.QtWidgets import QAction [as 别名]
# 或者: from qtpy.QtWidgets.QAction import setMenuRole [as 别名]
def create_action(parent, text, shortcut=None, icon=None, tip=None,
                  toggled=None, triggered=None, data=None, menurole=None,
                  context=Qt.WindowShortcut):
    """Create a QAction"""
    action = QAction(text, parent)
    if triggered is not None:
        action.triggered.connect(triggered)
    if toggled is not None:
        action.toggled.connect(toggled)
        action.setCheckable(True)
    if icon is not None:
        if is_text_string(icon):
            icon = get_icon(icon)
        action.setIcon(icon)
    if shortcut is not None:
        action.setShortcut(shortcut)
    if tip is not None:
        action.setToolTip(tip)
        action.setStatusTip(tip)
    if data is not None:
        action.setData(to_qvariant(data))
    if menurole is not None:
        action.setMenuRole(menurole)
    #TODO: Hard-code all shortcuts and choose context=Qt.WidgetShortcut
    # (this will avoid calling shortcuts from another dockwidget
    #  since the context thing doesn't work quite well with these widgets)
    action.setShortcutContext(context)
    return action
开发者ID:DLlearn,项目名称:spyder,代码行数:30,代码来源:qthelpers.py

示例2: create_action

# 需要导入模块: from qtpy.QtWidgets import QAction [as 别名]
# 或者: from qtpy.QtWidgets.QAction import setMenuRole [as 别名]
def create_action(parent, text, shortcut=None, icon=None, tip=None,
                  toggled=None, triggered=None, data=None, menurole=None,
                  context=Qt.WindowShortcut):
    """Create a QAction"""
    action = QAction(text, parent)
    if triggered is not None:
        action.triggered.connect(triggered)
    if toggled is not None:
        action.toggled.connect(toggled)
        action.setCheckable(True)
    if icon is not None:
        if is_text_string(icon):
            icon = get_icon(icon)
        action.setIcon(icon)
    if tip is not None:
        action.setToolTip(tip)
        action.setStatusTip(tip)
    if data is not None:
        action.setData(to_qvariant(data))
    if menurole is not None:
        action.setMenuRole(menurole)

    # Workround for Mac because setting context=Qt.WidgetShortcut
    # there doesn't have any effect
    if sys.platform == 'darwin':
        action._shown_shortcut = None
        if context == Qt.WidgetShortcut:
            if shortcut is not None:
                action._shown_shortcut = shortcut
            else:
                # This is going to be filled by
                # main.register_shortcut
                action._shown_shortcut = 'missing'
        else:
            if shortcut is not None:
                action.setShortcut(shortcut)
            action.setShortcutContext(context)
    else:
        if shortcut is not None:
            action.setShortcut(shortcut)
        action.setShortcutContext(context)

    return action
开发者ID:G-VAR,项目名称:spyder,代码行数:45,代码来源:qthelpers.py


注:本文中的qtpy.QtWidgets.QAction.setMenuRole方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。