本文整理汇总了Python中mathutils.Vector.inverted方法的典型用法代码示例。如果您正苦于以下问题：Python Vector.inverted方法的具体用法？Python Vector.inverted怎么用？Python Vector.inverted使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类mathutils.Vector的用法示例。
在下文中一共展示了Vector.inverted方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: OBB
# 需要导入模块: from mathutils import Vector [as 别名]
# 或者: from mathutils.Vector import inverted [as 别名]
#.........这里部分代码省略.........
mat.col[0][:2] = mat2.col[0]
mat.col[1][:2] = mat2.col[1]
mat.col[2][:2] = (v1 + v2) / 2
bb_size[0] = (v2 - v1).length
else:
yaxis = _closest_axis_on_plane(vecs, indices)
angle = math.atan2(yaxis[1], yaxis[0]) - math.pi / 2 # X軸
mat2 = Matrix.Rotation(angle, 2)
imat2 = Matrix.Rotation(-angle, 2)
rotvecs = [imat2 * v for v in vecs]
loc = Vector((0, 0))
for i in range(2):
rotvecs.sort(key=lambda v: v[i])
bb_size[i] = rotvecs[-1][i] - rotvecs[0][i]
loc[i] = (rotvecs[0][i] + rotvecs[-1][i]) / 2
mat.col[0][:2] = mat2.col[0]
mat.col[1][:2] = mat2.col[1]
mat.col[2][:2] = mat2 * loc
return mat, bb_size
# 3D ----------------------------------------------------------------------
mat = Matrix.Identity(4)
bb_size = Vector((0, 0, 0))
indices = convex_hull(vecs, eps)
if r_indices:
r_indices[:] = indices
if isinstance(indices[0], int): # 2d
if len(indices) == 1:
mat.col[3][:3] = vecs[0]
return mat, bb_size
elif len(indices) == 2:
# 同一線上
v1 = vecs[indices[0]]
v2 = vecs[indices[1]]
xaxis = (v2 - v1).normalized()
quat = Vector((1, 0, 0)).rotation_difference(xaxis)
mat = quat.to_matrix().to_4x4()
mat.col[3][:3] = (v1 + v2) / 2
bb_size[0] = (v2 - v1).length
return mat, bb_size
else:
# 同一平面上
medium = reduce(lambda a, b: a + b, vecs) / len(vecs)
v1 = max(vecs, key=lambda v: (v - medium).length)
v2 = max(vecs, key=lambda v: (v - v1).length)
line = v2 - v1
v3 = max(vecs, key=lambda v: line.cross(v - v1).length)
zaxis = geom.normal(v1, v2, v3)
if zaxis[2] < 0.0:
zaxis.negate()
quat = zaxis.rotation_difference(Vector((0, 0, 1)))
rotvecs = [quat * v for v in vecs]
indices_2d = indices
else: # 3d
indices_set = set(chain(*indices))
zaxis = None
dist = 0.0
# 最も距離の近い面（平面）と頂点を求める
for tri in indices:
v1, v2, v3 = [vecs[i] for i in tri]
normal = geom.normal(v1, v2, v3)
d = 0.0
for v4 in (vecs[i] for i in indices_set if i not in tri):
f = abs(geom.distance_point_to_plane(v4, v1, normal))
d = max(f, d)
if zaxis is None or d < dist:
zaxis = -normal
dist = d
quat = zaxis.rotation_difference(Vector((0, 0, 1)))
rotvecs = [(quat * v).to_2d() for v in vecs]
indices_2d = convex_hull_2d(rotvecs, eps)
yaxis = _closest_axis_on_plane(rotvecs, indices_2d)
yaxis = quat.inverted() * yaxis.to_3d()
xaxis = yaxis.cross(zaxis)
xaxis.normalize() # 不要？
mat.col[0][:3] = xaxis
mat.col[1][:3] = yaxis
mat.col[2][:3] = zaxis
# OBBの大きさと中心を求める
imat = mat.inverted()
rotvecs = [imat * v for v in vecs]
loc = Vector()
for i in range(3):
rotvecs.sort(key=lambda v: v[i])
bb_size[i] = rotvecs[-1][i] - rotvecs[0][i]
loc[i] = (rotvecs[0][i] + rotvecs[-1][i]) / 2
mat.col[3][:3] = mat * loc
return mat, bb_size