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Python Scheduler.clearW方法代码示例

本文整理汇总了Python中Scheduler.Scheduler.clearW方法的典型用法代码示例。如果您正苦于以下问题:Python Scheduler.clearW方法的具体用法?Python Scheduler.clearW怎么用?Python Scheduler.clearW使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Scheduler.Scheduler的用法示例。


在下文中一共展示了Scheduler.clearW方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: __init__

# 需要导入模块: from Scheduler import Scheduler [as 别名]
# 或者: from Scheduler.Scheduler import clearW [as 别名]

#.........这里部分代码省略.........
                times = self.getTimes()
                if times == "cancel": continue

                if type(days) != list:
                    days = [days]
                    
                if self.assignD(emp, days, times, lunch) == 1:
                    print("Successfully assigned %s to shifts %s on %s."%(emp.getName(),times, days))
                else:
                    print("Shifts not assigned.")

            elif command == "clear weekday" or command == "clr w":
                weekdays = self.getInputOfType("Clear a shift for which weekday(s)? (M,T,W,Th,F,S,Su) : ", "str", range(1,3))
                if weekdays == "cancel": continue
                print("")
                lunch = self.getLunch()
                if lunch == "cancel": continue
                allShifts = self.getInputOfType("Would you like to clear all shifts? (y/n) :", "bool")
                if allShifts == "cancel": continue
                print("")
                if not allShifts:
                    times = self.getTimes()
                    if times == "cancel": continue
                else:
                    times = "all"

                if type(weekdays) != list:
                    weekdays = [weekdays]
                
                weekdayAsNum = []
                for d in weekdays:
                    weekdayAsNum.append(self.weekdayAbbr[day.lower()])

                if self.scheduler.clearW(weekdayAsNum, times, lunch) == 1:
                    print("Successfully cleared shifts %s on %s."%(times, weekdays))
                else:
                    print("Shifts not cleared.")

            elif command == "clear day" or command == "clr d":
                days = self.getInputOfType("Clear a shift for which day(s)? : ", "int", range(1, self.scheduler.numDays+1))
                if days == "cancel": continue
                print("")
                lunch = self.getLunch()
                if lunch == "cancel": continue
                print("")
                allShifts = self.getInputOfType("Would you like to clear all shifts? (y/n) :", "bool")
                if allShifts == "cancel": continue
                print("")
                if not allShifts:
                    times = self.getTimes()
                    if times == "cancel": continue
                else:
                    times = "all"

                if type(days) != list:
                    days = [days]

                if self.scheduler.clearD(days, times, lunch) == 1:
                    print("Successfully cleared shifts %s on %s."%(times, days))
                else:
                    print("Shifts not cleared.")

            else:
                self.cmdNotRecognized(command)

    def getLunch(self):
开发者ID:calebawatts,项目名称:Shift-Scheduler,代码行数:70,代码来源:UI.py


注:本文中的Scheduler.Scheduler.clearW方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。