本文整理汇总了Python中PathScripts.PathGeom.PathGeom.arcToHelix方法的典型用法代码示例。如果您正苦于以下问题：Python PathGeom.arcToHelix方法的具体用法？Python PathGeom.arcToHelix怎么用？Python PathGeom.arcToHelix使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类PathScripts.PathGeom.PathGeom的用法示例。
在下文中一共展示了PathGeom.arcToHelix方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test65
# 需要导入模块: from PathScripts.PathGeom import PathGeom [as 别名]
# 或者: from PathScripts.PathGeom.PathGeom import arcToHelix [as 别名]
def test65(self):
"""Verify splitEdgeAt."""
e = PathGeom.splitEdgeAt(Part.Edge(Part.LineSegment(Vector(), Vector(2, 4, 6))), Vector(1, 2, 3))
self.assertLine(e[0], Vector(), Vector(1,2,3))
self.assertLine(e[1], Vector(1,2,3), Vector(2,4,6))
# split an arc
p1 = Vector(10,-10,1)
p2 = Vector(0,0,1)
p3 = Vector(10,10,1)
arc = Part.Edge(Part.Arc(p1, p2, p3))
e = PathGeom.splitEdgeAt(arc, p2)
o = 10*math.sin(math.pi/4)
p12 = Vector(10 - o, -o, 1)
p23 = Vector(10 - o, +o, 1)
self.assertCurve(e[0], p1, p12, p2)
self.assertCurve(e[1], p2, p23, p3)
# split a helix
p1 = Vector(10,-10,0)
p2 = Vector(0,0,5)
p3 = Vector(10,10,10)
h = PathGeom.arcToHelix(arc, 0, 10)
self.assertCurve(h, p1, p2, p3)
e = PathGeom.splitEdgeAt(h, p2)
o = 10*math.sin(math.pi/4)
p12 = Vector(10 - o, -o, 2.5)
p23 = Vector(10 - o, +o, 7.5)
pf = e[0].valueAt((e[0].FirstParameter + e[0].LastParameter)/2)
pl = e[1].valueAt((e[1].FirstParameter + e[1].LastParameter)/2)
self.assertCurve(e[0], p1, p12, p2)
self.assertCurve(e[1], p2, p23, p3)示例2: test60
# 需要导入模块: from PathScripts.PathGeom import PathGeom [as 别名]
# 或者: from PathScripts.PathGeom.PathGeom import arcToHelix [as 别名]
def test60(self):
"""Verify arcToHelix returns proper helix."""
p1 = Vector(10,-10,0)
p2 = Vector(0,0,0)
p3 = Vector(10,10,0)
e = PathGeom.arcToHelix(Part.Edge(Part.Arc(p1, p2, p3)), 0, 2)
self.assertCurve(e, p1, p2 + Vector(0,0,1), p3 + Vector(0,0,2))
e = PathGeom.arcToHelix(Part.Edge(Part.Arc(p1, p2, p3)), 3, 7)
self.assertCurve(e, p1 + Vector(0,0,3), p2 + Vector(0,0,5), p3 + Vector(0,0,7))
e = PathGeom.arcToHelix(Part.Edge(Part.Arc(p1, p2, p3)), 9, 1)
self.assertCurve(e, p1 + Vector(0,0,9), p2 + Vector(0,0,5), p3 + Vector(0,0,1))
dz = Vector(0,0,3)
p11 = p1 + dz
p12 = p2 + dz
p13 = p3 + dz
e = PathGeom.arcToHelix(Part.Edge(Part.Arc(p11, p12, p13)), 0, 8)
self.assertCurve(e, p1, p2 + Vector(0,0,4), p3 + Vector(0,0,8))
e = PathGeom.arcToHelix(Part.Edge(Part.Arc(p11, p12, p13)), 2, -2)
self.assertCurve(e, p1 + Vector(0,0,2), p2, p3 + Vector(0,0,-2))
o = 10*math.sin(math.pi/4)
p1 = Vector(10, -10, 1)
p2 = Vector(10 - 10*math.sin(math.pi/4), -10*math.cos(math.pi/4), 1)
p3 = Vector(0, 0, 1)
e = PathGeom.arcToHelix(Part.Edge(Part.Arc(p1, p2, p3)), 0, 5)
self.assertCurve(e, Vector(10,-10,0), Vector(p2.x,p2.y,2.5), Vector(0, 0, 5))