本文整理汇总了Python中MoinMoin.Page.Page.may方法的典型用法代码示例。如果您正苦于以下问题：Python Page.may方法的具体用法？Python Page.may怎么用？Python Page.may使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类MoinMoin.Page.Page的用法示例。
在下文中一共展示了Page.may方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: _check
# 需要导入模块: from MoinMoin.Page import Page [as 别名]
# 或者: from MoinMoin.Page.Page import may [as 别名]
def _check(request, pagename, username, right):
""" Check <right> access permission for user <username> on page <pagename>
For cfg.acl_hierarchic=False we just check the page in question.
For cfg.acl_hierarchic=True we, we check each page in the hierarchy. We
start with the deepest page and recurse to the top of the tree.
If one of those permits, True is returned.
For both configurations, we check acl_rights_before before the page/default
acl and acl_rights_after after the page/default acl, of course.
This method should not be called by users, use __getattr__ instead.
@param request: the current request object
@param pagename: pagename to get permissions from
@param username: the user name
@param right: the right to check
@rtype: bool
@return: True if you have permission or False
"""
cache = request.cfg.cache
allowed = cache.acl_rights_before.may(request, username, right)
if allowed is not None:
return allowed
if request.cfg.acl_hierarchic:
pages = pagename.split('/') # create page hierarchy list
some_acl = False
for i in range(len(pages), 0, -1):
# Create the next pagename in the hierarchy
# starting at the leaf, going to the root
name = '/'.join(pages[:i])
# Get page acl and ask for permission
acl = Page(request, name).getACL(request)
if acl.acl:
some_acl = True
allowed = acl.may(request, username, right)
if allowed is not None:
return allowed
if not some_acl:
allowed = cache.acl_rights_default.may(request, username, right)
if allowed is not None:
return allowed
else:
if request.page is not None and pagename == request.page.page_name:
p = request.page # reuse is good
else:
p = Page(request, pagename)
acl = p.getACL(request) # this will be fast in a reused page obj
allowed = acl.may(request, username, right)
if allowed is not None:
return allowed
allowed = cache.acl_rights_after.may(request, username, right)
if allowed is not None:
return allowed
return False