Python IITreeSet.clear方法代码示例

# 需要导入模块: from BTrees.IIBTree import IITreeSet [as 别名]
# 或者: from BTrees.IIBTree.IITreeSet import clear [as 别名]
class BooleanIndex(UnIndex):
    """Index for booleans

       self._index = set([documentId1, documentId2])
       self._unindex = {documentId:[True/False]}

       self._length is the length of the unindex
       self._index_length is the length of the index

       False doesn't have actual entries in _index.
    """

    meta_type = "BooleanIndex"

    manage_options = (
        {'label': 'Settings',
         'action': 'manage_main'},
        {'label': 'Browse',
         'action': 'manage_browse'},
    )

    query_options = ["query"]

    manage = manage_main = DTMLFile('dtml/manageBooleanIndex', globals())
    manage_main._setName('manage_main')
    manage_browse = DTMLFile('../dtml/browseIndex', globals())

    _index_value = 1
    _index_length = None

    def clear(self):
        self._index = IITreeSet()
        self._index_length = BTrees.Length.Length()
        self._index_value = 1
        self._unindex = IIBTree()
        self._length = BTrees.Length.Length()
        if self._counter is None:
            self._counter = BTrees.Length.Length()
        else:
            self._increment_counter()

    def histogram(self):
        """Return a mapping which provides a histogram of the number of
        elements found at each point in the index.
        """
        histogram = {}
        indexed = bool(self._index_value)
        histogram[indexed] = self._index_length.value
        histogram[not indexed] = self._length.value - self._index_length.value
        return histogram

    def _invert_index(self, documentId=None):
        self._index_value = indexed = int(not self._index_value)
        self._index.clear()
        length = 0
        for rid, value in self._unindex.iteritems():
            if value == indexed:
                self._index.add(rid)
                length += 1
        # documentId is the rid of the currently processed object that
        # triggered the invert. in the case of unindexing, the rid hasn't
        # been removed from the unindex yet. While indexing, the rid will
        # be added to the index and unindex after this method is done
        if documentId is not None:
            self._index.remove(documentId)
            length -= 1
        self._index_length = BTrees.Length.Length(length)

    def insertForwardIndexEntry(self, entry, documentId):
        """If the value matches the indexed one, insert into treeset
        """
        # When we get the first entry, decide to index the opposite of what
        # we got, as indexing zero items is fewer than one.
        if self._length.value == 0:
            self._index_value = int(not bool(entry))

        # if the added entry value is index value, insert it into index
        if bool(entry) is bool(self._index_value):
            self._index_length.change(1)
            self._index.insert(documentId)

        # insert value into global unindex (before computing index invert)
        self._unindex[documentId] = entry
        self._length.change(1)

        # is the index (after adding the current entry) larger than 60%
        # of the total length? than switch the indexed value
        if bool(entry) is bool(self._index_value):
            if (self._index_length.value) >= ((self._length.value) * 0.6):
                self._invert_index()

    def removeForwardIndexEntry(self, entry, documentId, check=True):
        """Take the entry provided and remove any reference to documentId
        in its entry in the index.
        """
        if bool(entry) is bool(self._index_value):
            try:
                self._index.remove(documentId)
                self._index_length.change(-1)
            except ConflictError:
#.........这里部分代码省略.........