本文整理汇总了Python中DatabaseController.insertNewClassroomRecord方法的典型用法代码示例。如果您正苦于以下问题：Python DatabaseController.insertNewClassroomRecord方法的具体用法？Python DatabaseController.insertNewClassroomRecord怎么用？Python DatabaseController.insertNewClassroomRecord使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类DatabaseController的用法示例。
在下文中一共展示了DatabaseController.insertNewClassroomRecord方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: insertNewClassroomRecord
# 需要导入模块: import DatabaseController [as 别名]
# 或者: from DatabaseController import insertNewClassroomRecord [as 别名]
def insertNewClassroomRecord(locationId, roomName):
classroomIdRecord = DatabaseController.getClassroomIdFromRoomName(roomName)
if classroomIdRecord.__len__() == 0:
DatabaseController.insertNewClassroomRecord(roomName)
classroomIdRecord = DatabaseController.getClassroomIdFromRoomName(roomName)
classroomId = int(classroomIdRecord[0][0])
DatabaseController.insertNewClassroomLocationRecord(locationId, classroomId)示例2: updateEditedClassroomRecord
# 需要导入模块: import DatabaseController [as 别名]
# 或者: from DatabaseController import insertNewClassroomRecord [as 别名]
def updateEditedClassroomRecord(oldLocationId, newLocationId, classroomId, roomName):
existingClassroomRecord = DatabaseController.getClassroomNameBasedOnIdAndLocation(oldLocationId, classroomId)
if existingClassroomRecord[0][0] == roomName:
DatabaseController.updateClassroomLocationId(oldLocationId, newLocationId, classroomId)
else:
duplicateCountRecord = DatabaseController.countDuplicateClassroomNames(roomName)
duplicateCount = int(duplicateCountRecord[0][0])
if duplicateCount == 0:
DatabaseController.insertNewClassroomRecord(roomName)
newClassroomIdRecord = DatabaseController.getClassroomIdBasedOnName(roomName)
newClassroomId = int(newClassroomIdRecord[0][0])
DatabaseController.updateClassroomLocationAndRoomId(oldLocationId, newLocationId, classroomId, newClassroomId)
manageClassroomUsage(classroomId)