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Python DatabaseController.getSchoolIdBasedOnEmailAddress方法代码示例

本文整理汇总了Python中DatabaseController.getSchoolIdBasedOnEmailAddress方法的典型用法代码示例。如果您正苦于以下问题:Python DatabaseController.getSchoolIdBasedOnEmailAddress方法的具体用法?Python DatabaseController.getSchoolIdBasedOnEmailAddress怎么用?Python DatabaseController.getSchoolIdBasedOnEmailAddress使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在DatabaseController的用法示例。


在下文中一共展示了DatabaseController.getSchoolIdBasedOnEmailAddress方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: verifyUserLoginDetails

# 需要导入模块: import DatabaseController [as 别名]
# 或者: from DatabaseController import getSchoolIdBasedOnEmailAddress [as 别名]
def verifyUserLoginDetails(emailAddress, password):
    schoolEmailCountRecord = DatabaseController.checkIfDuplicateSchoolEmail(emailAddress)
    schoolEmailCount = int(schoolEmailCountRecord[0][0])
    if schoolEmailCount > 0:
        schoolIdRecord = DatabaseController.getSchoolIdBasedOnEmailAddress(emailAddress)
        schoolId = int(schoolIdRecord[0][0])
        accountPasswordRecord = DatabaseController.getAccountPasswordBasedOnSchoolId(schoolId)
        accountPassword = accountPasswordRecord[0][0]
        if password == accountPassword:
            schoolNameRecord = DatabaseController.getSchoolNameBasedOnSchoolId(schoolId)
            schoolName = schoolNameRecord[0][0]
            session["loginId"] = schoolId
            session["loginName"] = schoolName
            session["loggedIn"] = True
            session["accountType"] = accountTypes[0]
            return True
        else:
            return False
    else:
        personEmailCountRecord = DatabaseController.countNumberOfDuplicatePersonEmailAddresses(emailAddress)
        personEmailCount = int(personEmailCountRecord[0][0])
        if personEmailCount > 0:
            personIdRecord = DatabaseController.getPersonIdBasedOnEmailAddress(emailAddress)
            personId = int(personIdRecord[0][0])
            accountPasswordRecord = DatabaseController.getAccountPasswordBasedOnPersonId(personId)
            if accountPasswordRecord.__len__() > 0:
                accountPassword = accountPasswordRecord[0][0]
                if password == accountPassword:
                    personNameRecord = DatabaseController.getPersonDetailsByPersonId(personId)
                    personName = "" + personNameRecord[0][0] + " " + personNameRecord[0][1]

                    accountTypeRecord = DatabaseController.getAccountTypeBasedOnPersonIdAndPassword(personId, accountPassword)
                    typeOfAccount = accountTypeRecord[0][0]
                    if typeOfAccount == "Teacher":
                        personIdRecord = DatabaseController.getTeacherIdFromPersonId(personId)
                        personId = int(personIdRecord[0][0])
                    elif typeOfAccount == "Student":
                        personIdRecord = DatabaseController.getStudentIdFromPersonId(personId)
                        personId = int(personIdRecord[0][0])
                    
                    session["loginId"] = personId
                    session["loginName"] = personName
                    session["loggedIn"] = True
                    session["accountType"] = accountTypeRecord[0][0]
                    return True
                else:
                    return False
            else:
                return False
        else:
            return False
开发者ID:ajc24,项目名称:ProjectY4,代码行数:53,代码来源:DataProcessing.py

示例2: insertNewSchoolRecord

# 需要导入模块: import DatabaseController [as 别名]
# 或者: from DatabaseController import getSchoolIdBasedOnEmailAddress [as 别名]
def insertNewSchoolRecord(schoolName, emailAddress, streetName1, streetName2, townOrCity, county, phoneNumber, password):
    headLocation = 1
    personId = 0
    weekdayId = 1
    duplicateRecord = DatabaseController.countNumberOfDuplicateAddresses(streetName1, streetName2, townOrCity, county)
    duplicateValue = int(duplicateRecord[0][0])
    if duplicateValue == 0:
        insertNewAddressRecord(streetName1, streetName2, townOrCity, county)
    addressIdRecord = DatabaseController.getAddressId(streetName1, streetName2, townOrCity, county)
    addressId = int(addressIdRecord[0][0])

    DatabaseController.insertNewSchoolRecord(schoolName, addressId, phoneNumber, emailAddress)
    schoolIdRecord = DatabaseController.getSchoolIdBasedOnEmailAddress(emailAddress)
    schoolId = int(schoolIdRecord[0][0])
    DatabaseController.insertNewSchoolAccountRecord(accountTypes[0], schoolId, personId, password)

    while weekdayId <= 7:
        DatabaseController.insertNewOpeningHoursRecord(schoolId, weekdayId)
        weekdayId += 1
    insertNewLocationRecord(schoolId, schoolName, streetName1, streetName2, townOrCity, county, headLocation)
开发者ID:ajc24,项目名称:ProjectY4,代码行数:22,代码来源:DataProcessing.py


注:本文中的DatabaseController.getSchoolIdBasedOnEmailAddress方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。