本文整理汇总了PHP中Skill::toString方法的典型用法代码示例。如果您正苦于以下问题：PHP Skill::toString方法的具体用法？PHP Skill::toString怎么用？PHP Skill::toString使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Skill的用法示例。
在下文中一共展示了Skill::toString方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: post
public function post($resourceVals, $data, $userId)
{
global $logger, $warnings_payload;
$userId = 5;
$skillId = $resourceVals['user-skills'];
if (isset($skillId)) {
$warnings_payload[] = 'POST call to /user-skills must not have ' . '/skillID appended i.e. POST /user-skills';
throw new UnsupportedResourceMethodException();
}
if ($data['name'] != null) {
$nameObj = $this->collapDAO->queryByName($data['name']);
if (empty($nameObj)) {
$skillObj = new Skill($data['name']);
$logger->debug("POSTed Skill Detail: " . $skillObj->toString());
$this->collapDAO->insert($skillObj);
$userSkillDetail = $skillObj->toArray();
if (isset($userSkillDetail['id'])) {
$userSkillObj = new UserSkill($userId, $userSkillDetail['id']);
$logger->debug("POSTed User Skill Detail: " . $userSkillObj->toString());
$this->collapDAO->insertUserSkill($userSkillObj);
$userSkillDetail = $userSkillObj->toArray();
}
} else {
$nameSkill = $nameObj[0]->toArray();
$userSkillObj = new UserSkill($userId, $nameSkill['id']);
$logger->debug("POSTed User Skill Detail: " . $userSkillObj->toString());
$this->collapDAO->insertUserSkill($userSkillObj);
$userSkillDetail = $userSkillObj->toArray();
}
} else {
$userSkillObj = new UserSkill($userId, $data['skill_id']);
$logger->debug("POSTed User Skill Detail: " . $userSkillObj->toString());
$this->collapDAO->insertUserSkill($userSkillObj);
$userSkillDetail = $userSkillObj->toArray();
}
if (!isset($userSkillDetail['id'])) {
return array('code' => '2011');
}
$this->userSkillDetail[] = $userSkillDetail;
return array('code' => '2001', 'data' => array('userSkillDetail' => $this->userSkillDetail));
}