本文整理汇总了PHP中ProjectManager::getTotalNumberOfProjects方法的典型用法代码示例。如果您正苦于以下问题：PHP ProjectManager::getTotalNumberOfProjects方法的具体用法？PHP ProjectManager::getTotalNumberOfProjects怎么用？PHP ProjectManager::getTotalNumberOfProjects使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ProjectManager的用法示例。
在下文中一共展示了ProjectManager::getTotalNumberOfProjects方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: count
$filteredProjects = [];
if (isset($_SESSION['filterResults']) && !empty($_SESSION['filterResults'])) {
//get total number of records from database
$filteredProjects = $_SESSION['filterResults'];
$totalNumberProjects = count($filteredProjects);
//break records into pages
$totalPages = ceil($totalNumberProjects / $itemPerPage);
//fetch position of record
$pagePosition = ($pageNumber - 1) * $itemPerPage;
//fetch paginated results
for ($i = $pagePosition; $i < min($pagePosition + $itemPerPage, $totalNumberProjects); $i++) {
array_push($results, $filteredProjects[$i]);
}
} else {
//get total number of records from database
$totalNumberProjects = $projectMgr->getTotalNumberOfProjects();
//break records into pages
$totalPages = ceil($totalNumberProjects / $itemPerPage);
//fetch position of record
$pagePosition = ($pageNumber - 1) * $itemPerPage;
//Fetch part of records using SQL LIMIT clause
$results = $projectMgr->getPaginatedResults($pagePosition, $itemPerPage);
}
//Display fetched records
if (!empty($results)) {
//$_SESSION['results'] = $filteredProjects;
?>
<div id='thumbnails' class='col-md-10'>
<?php
foreach ($results as $eachProject) {
$project_name = $eachProject["project_name"];