本文整理汇总了PHP中ProjectManager::filterProjectAlphabet方法的典型用法代码示例。如果您正苦于以下问题：PHP ProjectManager::filterProjectAlphabet方法的具体用法？PHP ProjectManager::filterProjectAlphabet怎么用？PHP ProjectManager::filterProjectAlphabet使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ProjectManager的用法示例。
在下文中一共展示了ProjectManager::filterProjectAlphabet方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的PHP代码示例。
示例1: addslashes
include_once "./Manager/ProjectManager.php";
include_once "./Manager/PhotoManager.php";
$filterType = addslashes(filter_input(INPUT_POST, 'filterType'));
$filterValue = filter_input(INPUT_POST, 'filterValue');
// PAGE NUMBER IS SET TO 1
$pageNumber = filter_input(INPUT_POST, 'page');
$projectMgr = new ProjectManager();
$photoMgr = new PhotoManager();
$filteredProjects = [];
$results = [];
$itemPerPage = 10;
if ($filterType == 'all') {
$filteredProjects = $projectMgr->getAllProjects();
} else {
if ($filterType == 'alphabet') {
$filteredProjects = $projectMgr->filterProjectAlphabet($filterValue);
} else {
$filteredProjects = $projectMgr->filterProject($filterType, $filterValue);
}
}
//get total number of records from database
$totalNumberProjects = count($filteredProjects);
//break records into pages
$totalPages = ceil($totalNumberProjects / $itemPerPage);
//fetch position of record
$pagePosition = ($pageNumber - 1) * $itemPerPage;
//Fetch part of records using SQL LIMIT clause
for ($i = $pagePosition; $i < min($pagePosition + $itemPerPage, $totalNumberProjects); $i++) {
array_push($results, $filteredProjects[$i]);
}
if (!empty($results)) {