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Java PathNavigateGround.getPath方法代码示例

本文整理汇总了Java中net.minecraft.pathfinding.PathNavigateGround.getPath方法的典型用法代码示例。如果您正苦于以下问题:Java PathNavigateGround.getPath方法的具体用法?Java PathNavigateGround.getPath怎么用?Java PathNavigateGround.getPath使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在net.minecraft.pathfinding.PathNavigateGround的用法示例。


在下文中一共展示了PathNavigateGround.getPath方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: shouldExecute

import net.minecraft.pathfinding.PathNavigateGround; //导入方法依赖的package包/类
/**
 * Returns whether the EntityAIBase should begin execution.
 */
public boolean shouldExecute()
{
    if (!this.theEntity.isCollidedHorizontally)
    {
        return false;
    }
    else
    {
        PathNavigateGround pathnavigateground = (PathNavigateGround)this.theEntity.getNavigator();
        PathEntity pathentity = pathnavigateground.getPath();

        if (pathentity != null && !pathentity.isFinished() && pathnavigateground.getEnterDoors())
        {
            for (int i = 0; i < Math.min(pathentity.getCurrentPathIndex() + 2, pathentity.getCurrentPathLength()); ++i)
            {
                PathPoint pathpoint = pathentity.getPathPointFromIndex(i);
                this.doorPosition = new BlockPos(pathpoint.xCoord, pathpoint.yCoord + 1, pathpoint.zCoord);

                if (this.theEntity.getDistanceSq((double)this.doorPosition.getX(), this.theEntity.posY, (double)this.doorPosition.getZ()) <= 2.25D)
                {
                    this.doorBlock = this.getBlockDoor(this.doorPosition);

                    if (this.doorBlock != null)
                    {
                        return true;
                    }
                }
            }

            this.doorPosition = (new BlockPos(this.theEntity)).up();
            this.doorBlock = this.getBlockDoor(this.doorPosition);
            return this.doorBlock != null;
        }
        else
        {
            return false;
        }
    }
}
 
开发者ID:Notoh,项目名称:DecompiledMinecraft,代码行数:43,代码来源:EntityAIDoorInteract.java

示例2: shouldExecute

import net.minecraft.pathfinding.PathNavigateGround; //导入方法依赖的package包/类
/**
 * Returns whether the EntityAIBase should begin execution.
 */
public boolean shouldExecute()
{
    if (!this.theEntity.isCollidedHorizontally)
    {
        return false;
    }
    else
    {
        PathNavigateGround pathnavigateground = (PathNavigateGround)this.theEntity.getNavigator();
        Path path = pathnavigateground.getPath();

        if (path != null && !path.isFinished() && pathnavigateground.getEnterDoors())
        {
            for (int i = 0; i < Math.min(path.getCurrentPathIndex() + 2, path.getCurrentPathLength()); ++i)
            {
                PathPoint pathpoint = path.getPathPointFromIndex(i);
                this.doorPosition = new BlockPos(pathpoint.xCoord, pathpoint.yCoord + 1, pathpoint.zCoord);

                if (this.theEntity.getDistanceSq((double)this.doorPosition.getX(), this.theEntity.posY, (double)this.doorPosition.getZ()) <= 2.25D)
                {
                    this.doorBlock = this.getBlockDoor(this.doorPosition);

                    if (this.doorBlock != null)
                    {
                        return true;
                    }
                }
            }

            this.doorPosition = (new BlockPos(this.theEntity)).up();
            this.doorBlock = this.getBlockDoor(this.doorPosition);
            return this.doorBlock != null;
        }
        else
        {
            return false;
        }
    }
}
 
开发者ID:sudofox,项目名称:Backmemed,代码行数:43,代码来源:EntityAIDoorInteract.java


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