本文整理汇总了Java中java.util.concurrent.ConcurrentNavigableMap.pollFirstEntry方法的典型用法代码示例。如果您正苦于以下问题：Java ConcurrentNavigableMap.pollFirstEntry方法的具体用法？Java ConcurrentNavigableMap.pollFirstEntry怎么用？Java ConcurrentNavigableMap.pollFirstEntry使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类java.util.concurrent.ConcurrentNavigableMap的用法示例。
在下文中一共展示了ConcurrentNavigableMap.pollFirstEntry方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: testPollFirstEntry
import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
* pollFirstEntry returns entries in order
*/
public void testPollFirstEntry() {
ConcurrentNavigableMap map = map5();
Map.Entry e = map.pollFirstEntry();
assertEquals(one, e.getKey());
assertEquals("A", e.getValue());
e = map.pollFirstEntry();
assertEquals(two, e.getKey());
map.put(one, "A");
e = map.pollFirstEntry();
assertEquals(one, e.getKey());
assertEquals("A", e.getValue());
e = map.pollFirstEntry();
assertEquals(three, e.getKey());
map.remove(four);
e = map.pollFirstEntry();
assertEquals(five, e.getKey());
try {
e.setValue("A");
shouldThrow();
} catch (UnsupportedOperationException success) {}
e = map.pollFirstEntry();
assertNull(e);
}
示例2: testDescendingPollFirstEntry
import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
* pollFirstEntry returns entries in order
*/
public void testDescendingPollFirstEntry() {
ConcurrentNavigableMap map = dmap5();
Map.Entry e = map.pollFirstEntry();
assertEquals(m1, e.getKey());
assertEquals("A", e.getValue());
e = map.pollFirstEntry();
assertEquals(m2, e.getKey());
map.put(m1, "A");
e = map.pollFirstEntry();
assertEquals(m1, e.getKey());
assertEquals("A", e.getValue());
e = map.pollFirstEntry();
assertEquals(m3, e.getKey());
map.remove(m4);
e = map.pollFirstEntry();
assertEquals(m5, e.getKey());
try {
e.setValue("A");
shouldThrow();
} catch (UnsupportedOperationException success) {}
e = map.pollFirstEntry();
assertNull(e);
}
示例3: main
import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
* @param args
*/
public static void main(String[] args) {
/*
* Create the navigable map
*/
ConcurrentSkipListMap<String, Contact> map = new ConcurrentSkipListMap<>();
/*
* Create an array to store the 26 threads that execute the tasks
*/
Thread threads[] = new Thread[26];
int counter = 0;
/*
* Execute the 26 tasks
*/
for (char i = 'A'; i <= 'Z'; i++) {
Task task = new Task(map, String.valueOf(i));
threads[counter] = new Thread(task);
threads[counter].start();
counter++;
}
/*
* Wait for the finalization of the threads
*/
for (Thread thread : threads) {
try {
thread.join();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
/*
* Write the size of the map
*/
System.out.printf("Main: Size of the map: %d\n", map.size());
/*
* Write the first element of the map
*/
Map.Entry<String, Contact> element;
Contact contact;
element = map.firstEntry();
contact = element.getValue();
System.out.printf("Main: First Entry: %s: %s\n", contact.getName(), contact.getPhone());
/*
* Write the last element of the map
*/
element = map.lastEntry();
contact = element.getValue();
System.out.printf("Main: Last Entry: %s: %s\n", contact.getName(), contact.getPhone());
/*
* Write a subset of the map
*/
System.out.printf("Main: Submap from A1996 to B1002: \n");
ConcurrentNavigableMap<String, Contact> submap = map.subMap("A1996", "B1002");
do {
element = submap.pollFirstEntry();
if (element != null) {
contact = element.getValue();
System.out.printf("%s: %s\n", contact.getName(), contact.getPhone());
}
} while (element != null);
}