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Java ConcurrentNavigableMap.keySet方法代码示例

本文整理汇总了Java中java.util.concurrent.ConcurrentNavigableMap.keySet方法的典型用法代码示例。如果您正苦于以下问题:Java ConcurrentNavigableMap.keySet方法的具体用法?Java ConcurrentNavigableMap.keySet怎么用?Java ConcurrentNavigableMap.keySet使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在java.util.concurrent.ConcurrentNavigableMap的用法示例。


在下文中一共展示了ConcurrentNavigableMap.keySet方法的6个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Java代码示例。

示例1: testKeySet

import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
 * keySet returns a Set containing all the keys
 */
public void testKeySet() {
    ConcurrentNavigableMap map = map5();
    Set s = map.keySet();
    assertEquals(5, s.size());
    assertTrue(s.contains(one));
    assertTrue(s.contains(two));
    assertTrue(s.contains(three));
    assertTrue(s.contains(four));
    assertTrue(s.contains(five));
}
 
开发者ID:AdoptOpenJDK,项目名称:openjdk-jdk10,代码行数:14,代码来源:ConcurrentSkipListSubMapTest.java

示例2: testKeySetOrder

import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
 * keySet is ordered
 */
public void testKeySetOrder() {
    ConcurrentNavigableMap map = map5();
    Set s = map.keySet();
    Iterator i = s.iterator();
    Integer last = (Integer)i.next();
    assertEquals(last, one);
    while (i.hasNext()) {
        Integer k = (Integer)i.next();
        assertTrue(last.compareTo(k) < 0);
        last = k;
    }
}
 
开发者ID:AdoptOpenJDK,项目名称:openjdk-jdk10,代码行数:16,代码来源:ConcurrentSkipListSubMapTest.java

示例3: testKeySetToArray

import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
 * keySet.toArray returns contains all keys
 */
public void testKeySetToArray() {
    ConcurrentNavigableMap map = map5();
    Set s = map.keySet();
    Object[] ar = s.toArray();
    assertTrue(s.containsAll(Arrays.asList(ar)));
    assertEquals(5, ar.length);
    ar[0] = m10;
    assertFalse(s.containsAll(Arrays.asList(ar)));
}
 
开发者ID:AdoptOpenJDK,项目名称:openjdk-jdk10,代码行数:13,代码来源:ConcurrentSkipListSubMapTest.java

示例4: testDescendingKeySet

import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
 * keySet returns a Set containing all the keys
 */
public void testDescendingKeySet() {
    ConcurrentNavigableMap map = dmap5();
    Set s = map.keySet();
    assertEquals(5, s.size());
    assertTrue(s.contains(m1));
    assertTrue(s.contains(m2));
    assertTrue(s.contains(m3));
    assertTrue(s.contains(m4));
    assertTrue(s.contains(m5));
}
 
开发者ID:AdoptOpenJDK,项目名称:openjdk-jdk10,代码行数:14,代码来源:ConcurrentSkipListSubMapTest.java

示例5: testDescendingKeySetOrder

import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
 * keySet is ordered
 */
public void testDescendingKeySetOrder() {
    ConcurrentNavigableMap map = dmap5();
    Set s = map.keySet();
    Iterator i = s.iterator();
    Integer last = (Integer)i.next();
    assertEquals(last, m1);
    while (i.hasNext()) {
        Integer k = (Integer)i.next();
        assertTrue(last.compareTo(k) > 0);
        last = k;
    }
}
 
开发者ID:AdoptOpenJDK,项目名称:openjdk-jdk10,代码行数:16,代码来源:ConcurrentSkipListSubMapTest.java

示例6: testDescendingAscendingKeySetToArray

import java.util.concurrent.ConcurrentNavigableMap; //导入方法依赖的package包/类
/**
 * keySet.toArray returns contains all keys
 */
public void testDescendingAscendingKeySetToArray() {
    ConcurrentNavigableMap map = dmap5();
    Set s = map.keySet();
    Object[] ar = s.toArray();
    assertTrue(s.containsAll(Arrays.asList(ar)));
    assertEquals(5, ar.length);
    ar[0] = m10;
    assertFalse(s.containsAll(Arrays.asList(ar)));
}
 
开发者ID:AdoptOpenJDK,项目名称:openjdk-jdk10,代码行数:13,代码来源:ConcurrentSkipListSubMapTest.java


注:本文中的java.util.concurrent.ConcurrentNavigableMap.keySet方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。