本文整理汇总了Java中java.time.LocalDateTime.minusSeconds方法的典型用法代码示例。如果您正苦于以下问题：Java LocalDateTime.minusSeconds方法的具体用法？Java LocalDateTime.minusSeconds怎么用？Java LocalDateTime.minusSeconds使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类java.time.LocalDateTime的用法示例。
在下文中一共展示了LocalDateTime.minusSeconds方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: main
import java.time.LocalDateTime; //导入方法依赖的package包/类
public static void main(String[] args) {
/*LocalDate date = LocalDate.of(2014, Month.JANUARY, 20);
System.out.println(date);
date = date.plusDays(2);
System.out.println(date);
date = date.plusWeeks(1);
System.out.println(date);
date = date.plusMonths(1);
System.out.println(date);
date = date.plusYears(5);
System.out.println(date);*/
LocalDate date = LocalDate.of(2020, Month.JANUARY, 20);
LocalTime time = LocalTime.of(5, 15);
LocalDateTime dateTime = LocalDateTime.of(date, time);
System.out.println(dateTime);
dateTime = dateTime.minusDays(1);
System.out.println(dateTime);
dateTime = dateTime.minusHours(10);
System.out.println(dateTime);
dateTime = dateTime.minusSeconds(30);
System.out.println(dateTime);
}
示例2: test_toEpochSecond_beforeEpoch
import java.time.LocalDateTime; //导入方法依赖的package包/类
@Test
public void test_toEpochSecond_beforeEpoch() {
LocalDateTime ldt = LocalDateTime.of(1970, 1, 1, 0, 0).plusHours(1);
for (int i = 0; i < 100000; i++) {
ZonedDateTime a = ZonedDateTime.of(ldt, ZONE_PARIS);
assertEquals(a.toEpochSecond(), -i);
ldt = ldt.minusSeconds(1);
}
}
示例3: test_minusSeconds_one
import java.time.LocalDateTime; //导入方法依赖的package包/类
@Test
public void test_minusSeconds_one() {
LocalDateTime t = TEST_2007_07_15_12_30_40_987654321.with(LocalTime.MIDNIGHT);
LocalDate d = t.toLocalDate().minusDays(1);
int hour = 0;
int min = 0;
int sec = 0;
for (int i = 0; i < 3700; i++) {
t = t.minusSeconds(1);
sec--;
if (sec == -1) {
min--;
sec = 59;
if (min == -1) {
hour--;
min = 59;
if (hour == -1) {
hour = 23;
}
}
}
assertEquals(t.toLocalDate(), d);
assertEquals(t.getHour(), hour);
assertEquals(t.getMinute(), min);
assertEquals(t.getSecond(), sec);
}
}
示例4: test_minusSeconds_fromZero
import java.time.LocalDateTime; //导入方法依赖的package包/类
@Test(dataProvider="minusSeconds_fromZero")
public void test_minusSeconds_fromZero(int seconds, LocalDate date, int hour, int min, int sec) {
LocalDateTime base = TEST_2007_07_15_12_30_40_987654321.with(LocalTime.MIDNIGHT);
LocalDateTime t = base.minusSeconds(seconds);
assertEquals(date, t.toLocalDate());
assertEquals(hour, t.getHour());
assertEquals(min, t.getMinute());
assertEquals(sec, t.getSecond());
}
示例5: testClac
import java.time.LocalDateTime; //导入方法依赖的package包/类
/**
* 时间计算,减法操作
*/
@Test
public void testClac(){
LocalDateTime ldt = LocalDateTime.now();
System.out.println(ldt);
// 减: 天
LocalDateTime days = ldt.minusDays(1);
System.out.println("day: " + days);
// 减: 小时
LocalDateTime hours = ldt.minusHours(1);
System.out.println("hours: " + hours);
// 减: 分钟
LocalDateTime minutes = ldt.minusMinutes(1);
System.out.println("minutes: " + minutes);
// 减: 月
LocalDateTime months = ldt.minusMonths(1);
System.out.println("months: " + months);
// 减: 纳秒
LocalDateTime nanos = ldt.minusNanos(1);
System.out.println("nanos: " + nanos);
// 减: 秒
LocalDateTime seconds = ldt.minusSeconds(1);
System.out.println("seconds: " + seconds);
// 减: 周
LocalDateTime weeks = ldt.minusWeeks(1);
System.out.println("weeks: " + weeks);
// 减: 年
LocalDateTime years = ldt.minusYears(1);
System.out.println("years: " + years);
System.out.println(ldt);
}