本文整理汇总了Java中com.google.javascript.rhino.Node.isUnscopedQualifiedName方法的典型用法代码示例。如果您正苦于以下问题：Java Node.isUnscopedQualifiedName方法的具体用法？Java Node.isUnscopedQualifiedName怎么用？Java Node.isUnscopedQualifiedName使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类com.google.javascript.rhino.Node的用法示例。
在下文中一共展示了Node.isUnscopedQualifiedName方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: getClassesDefinedByCall
import com.google.javascript.rhino.Node; //导入方法依赖的package包/类
/**
* {@inheritDoc}
*
* <p>Understands several different inheritance patterns that occur in
* Google code (various uses of {@code inherits} and {@code mixin}).
*/
@Override
public SubclassRelationship getClassesDefinedByCall(Node callNode) {
Node callName = callNode.getFirstChild();
SubclassType type = typeofClassDefiningName(callName);
if (type != null) {
Node subclass = null;
Node superclass = callNode.getLastChild();
// There are six possible syntaxes for a class-defining method:
// SubClass.inherits(SuperClass)
// goog.inherits(SubClass, SuperClass)
// goog$inherits(SubClass, SuperClass)
// SubClass.mixin(SuperClass.prototype)
// goog.mixin(SubClass.prototype, SuperClass.prototype)
// goog$mixin(SubClass.prototype, SuperClass.prototype)
if (callNode.getChildCount() == 2 &&
callName.getType() == Token.GETPROP) {
// SubClass.inherits(SuperClass)
subclass = callName.getFirstChild();
} else if (callNode.getChildCount() == 3) {
// goog.inherits(SubClass, SuperClass)
subclass = callName.getNext();
}
// bail out if either of the side of the "inherits"
// isn't a real class name. This prevents us from
// doing something weird in cases like:
// goog.inherits(MySubClass, cond ? SuperClass1 : BaseClass2)
if (subclass != null &&
subclass.isUnscopedQualifiedName() &&
superclass.isUnscopedQualifiedName()) {
// make sure to strip the prototype off of the nodes
// to normalize for goog.mixin
return new SubclassRelationship(
type,
stripPrototype(subclass),
stripPrototype(superclass));
}
}
return null;
}