本文整理汇总了Java中com.google.javascript.rhino.Node.detachChildren方法的典型用法代码示例。如果您正苦于以下问题：Java Node.detachChildren方法的具体用法？Java Node.detachChildren怎么用？Java Node.detachChildren使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类com.google.javascript.rhino.Node的用法示例。
在下文中一共展示了Node.detachChildren方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: removeChild
import com.google.javascript.rhino.Node; //导入方法依赖的package包/类
/** Safely remove children while maintaining a valid node structure. */
static void removeChild(Node parent, Node node) {
// Node parent = node.getParent();
if (isStatementBlock(parent)
|| isSwitchCase(node)
|| isTryFinallyNode(parent, node)) {
// A statement in a block can simply be removed.
parent.removeChild(node);
} else if (parent.getType() == Token.VAR) {
if (parent.hasMoreThanOneChild()) {
parent.removeChild(node);
} else {
// Remove the node from the parent, so it can be reused.
parent.removeChild(node);
// This would leave an empty VAR, remove the VAR itself.
removeChild(parent.getParent(), parent);
}
} else if (node.getType() == Token.BLOCK) {
// Simply empty the block. This maintains source location and
// "synthetic"-ness.
node.detachChildren();
} else if (parent.getType() == Token.LABEL
&& node == parent.getLastChild()) {
// Remove the node from the parent, so it can be reused.
parent.removeChild(node);
// A LABEL without children can not be referred to, remove it.
removeChild(parent.getParent(), parent);
} else if (parent.getType() == Token.FOR
&& parent.getChildCount() == 4) {
// Only Token.FOR can have an Token.EMPTY other control structure
// need something for the condition. Others need to be replaced
// or the structure removed.
parent.replaceChild(node, new Node(Token.EMPTY));
} else {
throw new IllegalStateException("Invalid attempt to remove node: " +
node.toString() + " of "+ parent.toString());
}
}