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C# Enumerable.Intersect方法代码示例

本文整理汇总了C#中System.Linq.Enumerable.Intersect方法的典型用法代码示例。如果您正苦于以下问题:C# Enumerable.Intersect方法的具体用法?C# Enumerable.Intersect怎么用?C# Enumerable.Intersect使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。


在下文中一共展示了Enumerable.Intersect方法的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: Equals

public class Product
{
    public string Name { get; set; }
    public int Code { get; set; }
}

// Custom comparer for the Product class
class ProductComparer : IEqualityComparer<Product>
{
    // Products are equal if their names and product numbers are equal.
    public bool Equals(Product x, Product y)
    {
       
        //Check whether the compared objects reference the same data.
        if (Object.ReferenceEquals(x, y)) return true;

        //Check whether any of the compared objects is null.
        if (Object.ReferenceEquals(x, null) || Object.ReferenceEquals(y, null))
            return false;

        //Check whether the products' properties are equal.
        return x.Code == y.Code && x.Name == y.Name;
    }

    // If Equals() returns true for a pair of objects 
    // then GetHashCode() must return the same value for these objects.

    public int GetHashCode(Product product)
    {
        //Check whether the object is null
        if (Object.ReferenceEquals(product, null)) return 0;

        //Get hash code for the Name field if it is not null.
        int hashProductName = product.Name == null ? 0 : product.Name.GetHashCode();

        //Get hash code for the Code field.
        int hashProductCode = product.Code.GetHashCode();

        //Calculate the hash code for the product.
        return hashProductName ^ hashProductCode;
    }
}
开发者ID:.NET开发者,项目名称:System.Linq,代码行数:42,代码来源:Enumerable.Intersect

示例2:

Product[] store1 = { new Product { Name = "apple", Code = 9 }, 
                       new Product { Name = "orange", Code = 4 } };

Product[] store2 = { new Product { Name = "apple", Code = 9 }, 
                       new Product { Name = "lemon", Code = 12 } };
开发者ID:.NET开发者,项目名称:System.Linq,代码行数:5,代码来源:Enumerable.Intersect

示例3: ProductComparer

// Get the products from the first array 
// that have duplicates in the second array.

IEnumerable<Product> duplicates =
    store1.Intersect(store2, new ProductComparer());

foreach (var product in duplicates)
    Console.WriteLine(product.Name + " " + product.Code);
开发者ID:.NET开发者,项目名称:System.Linq,代码行数:8,代码来源:Enumerable.Intersect

输出:

apple 9

示例4:

int[] id1 = { 44, 26, 92, 30, 71, 38 };
int[] id2 = { 39, 59, 83, 47, 26, 4, 30 };

IEnumerable<int> both = id1.Intersect(id2);

foreach (int id in both)
    Console.WriteLine(id);
开发者ID:.NET开发者,项目名称:System.Linq,代码行数:7,代码来源:Enumerable.Intersect

输出:

26
 30

示例5: Equals

public class ProductA: IEquatable<ProductA>
{
    public string Name { get; set; }
    public int Code { get; set; }

    public bool Equals(ProductA other)
    {
        if (other is null)
            return false;

        return this.Name == other.Name && this.Code == other.Code;
    }

    public override bool Equals(object obj) => Equals(obj as ProductA);
    public override int GetHashCode() => (Name, Code).GetHashCode();
}
开发者ID:.NET开发者,项目名称:System.Linq,代码行数:16,代码来源:Enumerable.Intersect

示例6:

ProductA[] store1 = { new ProductA { Name = "apple", Code = 9 }, 
                       new ProductA { Name = "orange", Code = 4 } };

ProductA[] store2 = { new ProductA { Name = "apple", Code = 9 }, 
                       new ProductA { Name = "lemon", Code = 12 } };
开发者ID:.NET开发者,项目名称:System.Linq,代码行数:5,代码来源:Enumerable.Intersect

示例7:

// Get the products from the first array 
// that have duplicates in the second array.

IEnumerable<ProductA> duplicates =
    store1.Intersect(store2);

foreach (var product in duplicates)
    Console.WriteLine(product.Name + " " + product.Code);
开发者ID:.NET开发者,项目名称:System.Linq,代码行数:8,代码来源:Enumerable.Intersect

输出:

apple 9


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