本文整理汇总了C#中System.Linq.Enumerable.GroupBy方法的典型用法代码示例。如果您正苦于以下问题：C# Enumerable.GroupBy方法的具体用法？C# Enumerable.GroupBy怎么用？C# Enumerable.GroupBy使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。
在下文中一共展示了Enumerable.GroupBy方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: GroupByEx4
class Pet
{
public string Name { get; set; }
public double Age { get; set; }
}
public static void GroupByEx4()
{
// Create a list of pets.
List<Pet> petsList =
new List<Pet>{ new Pet { Name="Barley", Age=8.3 },
new Pet { Name="Boots", Age=4.9 },
new Pet { Name="Whiskers", Age=1.5 },
new Pet { Name="Daisy", Age=4.3 } };
// Group Pet.Age values by the Math.Floor of the age.
// Then project an anonymous type from each group
// that consists of the key, the count of the group's
// elements, and the minimum and maximum age in the group.
var query = petsList.GroupBy(
pet => Math.Floor(pet.Age),
pet => pet.Age,
(baseAge, ages) => new
{
Key = baseAge,
Count = ages.Count(),
Min = ages.Min(),
Max = ages.Max()
});
// Iterate over each anonymous type.
foreach (var result in query)
{
Console.WriteLine("\nAge group: " + result.Key);
Console.WriteLine("Number of pets in this age group: " + result.Count);
Console.WriteLine("Minimum age: " + result.Min);
Console.WriteLine("Maximum age: " + result.Max);
}
/* This code produces the following output:
Age group: 8
Number of pets in this age group: 1
Minimum age: 8.3
Maximum age: 8.3
Age group: 4
Number of pets in this age group: 2
Minimum age: 4.3
Maximum age: 4.9
Age group: 1
Number of pets in this age group: 1
Minimum age: 1.5
Maximum age: 1.5
*/
}示例2: GroupByEx1
class Pet
{
public string Name { get; set; }
public int Age { get; set; }
}
// Uses method-based query syntax.
public static void GroupByEx1()
{
// Create a list of pets.
List<Pet> pets =
new List<Pet>{ new Pet { Name="Barley", Age=8 },
new Pet { Name="Boots", Age=4 },
new Pet { Name="Whiskers", Age=1 },
new Pet { Name="Daisy", Age=4 } };
// Group the pets using Age as the key value
// and selecting only the pet's Name for each value.
IEnumerable<IGrouping<int, string>> query =
pets.GroupBy(pet => pet.Age, pet => pet.Name);
// Iterate over each IGrouping in the collection.
foreach (IGrouping<int, string> petGroup in query)
{
// Print the key value of the IGrouping.
Console.WriteLine(petGroup.Key);
// Iterate over each value in the
// IGrouping and print the value.
foreach (string name in petGroup)
Console.WriteLine(" {0}", name);
}
}输出：
8 Barley 4 Boots Daisy 1 Whiskers
示例3:
IEnumerable<IGrouping<int, string>> query =
from pet in pets
group pet.Name by pet.Age;示例4: GroupByEx3
class Pet
{
public string Name { get; set; }
public double Age { get; set; }
}
public static void GroupByEx3()
{
// Create a list of pets.
List<Pet> petsList =
new List<Pet>{ new Pet { Name="Barley", Age=8.3 },
new Pet { Name="Boots", Age=4.9 },
new Pet { Name="Whiskers", Age=1.5 },
new Pet { Name="Daisy", Age=4.3 } };
// Group Pet objects by the Math.Floor of their age.
// Then project an anonymous type from each group
// that consists of the key, the count of the group's
// elements, and the minimum and maximum age in the group.
var query = petsList.GroupBy(
pet => Math.Floor(pet.Age),
(age, pets) => new
{
Key = age,
Count = pets.Count(),
Min = pets.Min(pet => pet.Age),
Max = pets.Max(pet => pet.Age)
});
// Iterate over each anonymous type.
foreach (var result in query)
{
Console.WriteLine("\nAge group: " + result.Key);
Console.WriteLine("Number of pets in this age group: " + result.Count);
Console.WriteLine("Minimum age: " + result.Min);
Console.WriteLine("Maximum age: " + result.Max);
}
/* This code produces the following output:
Age group: 8
Number of pets in this age group: 1
Minimum age: 8.3
Maximum age: 8.3
Age group: 4
Number of pets in this age group: 2
Minimum age: 4.3
Maximum age: 4.9
Age group: 1
Number of pets in this age group: 1
Minimum age: 1.5
Maximum age: 1.5
*/
}