本文整理汇总了C#中Vector2f.Magnitude方法的典型用法代码示例。如果您正苦于以下问题：C# Vector2f.Magnitude方法的具体用法？C# Vector2f.Magnitude怎么用？C# Vector2f.Magnitude使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Vector2f的用法示例。
在下文中一共展示了Vector2f.Magnitude方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: BoundToWindow
private static void BoundToWindow(Shape shape)
{
Vector2f pos = shape.Position;
Vector2f newPos = pos;
Vector2f torquePoint = new Vector2f();
// horizontal bounds
if(shape.HasVertexOver(0, true, true, ref torquePoint) || shape.HasVertexOver(window.Size.X, true, false, ref torquePoint))
{
// apply a force to invert the shape's velocity
var pointsVelocity = shape.Velocity.X + shape.AngularVelocity * torquePoint.Magnitude();
Vector2f force = new Vector2f(shape.mass * -2 * pointsVelocity, 0);
shape.ApplyTorque(force, torquePoint);
}
// vertical bounds
if(shape.HasVertexOver(0, false, true, ref torquePoint) || shape.HasVertexOver(window.Size.Y, false, false, ref torquePoint))
{
// apply a force to invert the shape's velocity
var pointsVelocity = shape.Velocity.Y + shape.AngularVelocity * torquePoint.Magnitude();
Vector2f force = new Vector2f(0, shape.mass * -2 * pointsVelocity);
shape.ApplyTorque(force, torquePoint);
}
// bound position to window
Vector2f oppositeVelocity = new Vector2f();
if(pos.X < 0)
{
newPos.X = 0;
oppositeVelocity.X = -2 * shape.Velocity.X;
}
else if(pos.X > window.Size.X)
{
newPos.X = window.Size.X;
oppositeVelocity.X = -2 * shape.Velocity.X;
}
if(pos.Y < 0)
{
newPos.Y = 0;
oppositeVelocity.Y = -2 * shape.Velocity.Y;
}
else if(pos.Y > window.Size.Y)
{
newPos.Y = window.Size.Y;
oppositeVelocity.Y = -2 * shape.Velocity.Y;
}
// apply
shape.Position = newPos;
shape.ApplyForce(shape.mass * oppositeVelocity / dt.AsSeconds() * COLLISION_RATIO);
}示例2: ApplyTorque
// apply a force at 'fromCenter' relative to center of the shape
public void ApplyTorque(Vector2f force, Vector2f fromCenter)
{
var radius = fromCenter.Magnitude();
// check if 'fromCenter' is outside of the shape.
if(radius > GetRadiusOn(fromCenter))
return;
// torque is the amount of force in the perpendicular direction
var torque = force.Cross(fromCenter);
// linear force is the amount of force in the parallel direction
var linearForce = force.Dot(fromCenter) / (radius != 0 ? radius : 1f);
// moment of inertia of the mass at this radius
var inertia = mass * radius * radius;
AngularAcceleration += -torque / (inertia != 0 ? inertia : 1);
ApplyForce(linearForce * force.Unit());
}示例3: IsSmaller
private static bool IsSmaller(Vector2f left, Vector2f right)
{
return Math.Abs(left.Magnitude()) < Math.Abs(right.Magnitude());
}