本文整理汇总了C#中Tree.GetTreeNodeChild方法的典型用法代码示例。如果您正苦于以下问题：C# Tree.GetTreeNodeChild方法的具体用法？C# Tree.GetTreeNodeChild怎么用？C# Tree.GetTreeNodeChild使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Tree的用法示例。
在下文中一共展示了Tree.GetTreeNodeChild方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: OperateTreeNode
//// NodeId: id, NodeInfo: nodeInfo, XmlUrl: temp.xmlUrl
public ActionResult OperateTreeNode(string modeType, string _modeType, string nodeId, string nodeInfo, string xmlUrl)
{
using (RRDLEntities db = new RRDLEntities())
{
Tree tree = new Tree();
TreeNode treeNode = null;
switch (modeType)
{
case "rename":
string id = nodeId;
string name = nodeInfo;
treeNode = tree.GetTreeNodeById(Int32.Parse(id));
treeNode.Title = name;
tree.UpdateTreeNode(treeNode);
returnStr = "ok&" + treeNode.ParentId;
break;
case "delete":
returnStr = DeleteNode(_modeType, nodeId, xmlUrl);
break;
case "insert":
//List<NodeInfo> nodeList = this.GetListFromJson(nodeInfo);
//returnStr = this.InserNode(_modeType, nodeId, xmlUrl, nodeList);
//bool flag = true;
Tree tree2 = new Tree(db);
List<TreeNode> list = tree2.GetTreeNodeChild(Int32.Parse(nodeId));
//for (int i = 0; i < list.Count;i++ )
//{
// if(list[i].Ariticle != null){
// flag = false;
// }
//}
//if (flag)
//{
treeNode = new TreeNode(Int32.Parse(nodeId), "新建节点");
tree.AddTreeNode(treeNode);
returnStr = "ok";
//}
//else {
// returnStr = "该节点下存在文章,不能添加文件夹！";
//}
break;
}
return Content(returnStr);
}
}示例2: DeleteNode
//The Function Bllew is Added By ZHAOs ，2013年11月14日10:02:13，used to Delete A TreeNode in 目录树管理
public string DeleteNode(string _modeType, string nodeId, string xmlUrl) {
// _modeType = "deleteFolder" ,modeId = "6" ,xmlUrl = "" 传入的参数大致形式如此
Tree tree = new Tree();
TreeNode treeNode = tree.GetTreeNodeById(Convert.ToInt32(nodeId));
string returnStr = "";
/*
如果这个节点是叶子节点
如果是空文件夹 --文件夹（ariticleID为空且isLeaf属性为True），为空文件夹 ===> 可删除
如果是知识 --不能删除知识 （此时 ariticleID属性不为NULL 且 idLeaf属性为 True即是）
如果这个节点不是叶子节点（即非空文件夹，里面可能有知识或者 为空不为空的 文件夹）（ariticleID为空且isLeaf属性为false）====> 不能删除
PS:但是这里不显示知识，所以只可能有 叶子节点文件夹 和 非叶子节点文件夹。
* 叶子节点文件夹内部一定没有知识，可以直接删除 ===>有知识的情况 以后版本考虑
* 非叶子节点文件夹内容一定有文件夹或知识，不能删除。
* 逻辑较简单。
* 只是只能从叶子节点删起
* PS：如果一个父节点其下的所有子节点都被删除，则该父节点的IsLeaf属性变为True
*/
if (treeNode.IsLeaf == true)
{
//如果是根目录
if (treeNode.ParentId == null)
{
returnStr = "根目录不可删除！";
}
else {//若果其父节点下只有这一个子节点，则删除此子节点并把父节点isLeaf属性设为True
TreeNode parentNode = tree.GetTreeNodeById(Convert.ToInt32(treeNode.ParentId));
List<TreeNode> parentChildList = tree.GetTreeNodeChild(Convert.ToInt32(treeNode.ParentId));
if (parentChildList.Count == 1)
{
parentNode.IsLeaf = true;
}
tree.UpdateTreeNode(parentNode);//改变父节点isLeaf属性
tree.Drop(treeNode);//删除子节点
returnStr = "ok";
}
}
else {
returnStr = "该节点下存在子文件夹或知识，不能删除！";
}
return returnStr;
}示例3: GetTreeByRootIdForTreeManage
public ActionResult GetTreeByRootIdForTreeManage(string nodeId, string treeName)
{
using (RRDLEntities db = new RRDLEntities())
{
Tree tree = new Tree(db);
TreeNode rootNode = tree.GetRootNode(treeName);
string result = "";
if (nodeId != "")
{
int rootId = Int32.Parse(nodeId);
List<TreeNode> list = tree.GetTreeNodeChild(rootId);
TreeViewModel tvm = new TreeViewModel();
List<TreeViewModel> tlist = new List<TreeViewModel>();
for (int i = 0; i < list.Count; i++)
{
if (list[i].Ariticle == null)
{
tvm = new TreeViewModel();
tvm.Deepth = list[i].Deepth;
tvm.Id = list[i].Id;
tvm.IsLeaf = false;
tvm.ParentId = list[i].ParentId;
tvm.Title = list[i].Title;
tlist.Add(tvm);
}
}
result = JsonConvert.SerializeObject(tlist);
}
else
{
result = "[{\"Ariticle\":\"null\",\"Id\":\"" + rootNode.Id + "\",\"Title\":\"" + rootNode.Title + "\",\"Deepth\":\"" + rootNode.Deepth + "\",\"ParentId\":\"null\",\"IsLeaf\":\"" + rootNode.IsLeaf + "\"}]";
}
// List<TreeNode>
return Content(result);
}
}示例4: isAdd
//判断选择节点是否正确
public string isAdd(string treeNode) {
using (RRDLEntities db = new RRDLEntities())
{
Tree tree = new Tree(db);
List<TreeNode> list = tree.GetTreeNodeChild(Int32.Parse(treeNode));
string flag = "";
if (list.Count > 0)
{
if (list[0].Ariticle != null)
{
flag = "true";
}
}
else {
flag = "true";
}
return flag;
}
}示例5: ReadTreeNodes
public List<ClassifyTreeNodes> ReadTreeNodes(List<ClassifyTreeNodes> treeNodes, int? id)
{
Tree tree = new Tree();
List<TreeNode> newTreeNodes = tree.GetParentsTreeNodes(id);
List<ClassifyTreeNodes> treeNodeLists = new List<ClassifyTreeNodes>();
for (int i = 0; i < newTreeNodes.Count; i++)
{
ClassifyTreeNodes treeNode = new ClassifyTreeNodes();
treeNode.Title = newTreeNodes[i].Title;
//treeNode.AriticleId = newTreeNodes[i].Ariticle.Id;
treeNode.Id = newTreeNodes[i].Id;
treeNode.ParentId = newTreeNodes[i].ParentId;
treeNode.IsLeaf = newTreeNodes[i].IsLeaf;
if (treeNode.ParentId == null) {
treeNodes.Add(treeNode);
treeNodeLists.Add(treeNode);
}
//if (treeNode.IsLeaf == false)
//{
// ReadTreeNodes(treeNodes, treeNode.Id);
//}
}
for (int j = 0; j < treeNodes.Count; j++)
{
List<TreeNode> tns = new List<TreeNode>();
tns = tree.GetTreeNodeChild(Int32.Parse(treeNodes[j].Id.ToString()));
for (int k = 0; k < tns.Count; k++) {
TreeNode treeNode = tree.GetTreeNodeById(Int32.Parse(tns[k].Id.ToString()));
ClassifyTreeNodes classifyTreeNodes = new ClassifyTreeNodes();
classifyTreeNodes.Id = treeNode.Id;
classifyTreeNodes.IsLeaf = treeNode.IsLeaf;
classifyTreeNodes.ParentId = treeNode.ParentId;
classifyTreeNodes.Title = treeNode.Title;
treeNodeLists.Add(classifyTreeNodes);
}
}
return treeNodeLists;
}