本文整理汇总了C#中Tree.GetTreeNodeById方法的典型用法代码示例。如果您正苦于以下问题:C# Tree.GetTreeNodeById方法的具体用法?C# Tree.GetTreeNodeById怎么用?C# Tree.GetTreeNodeById使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Tree
的用法示例。
在下文中一共展示了Tree.GetTreeNodeById方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: OperateTreeNode
//// NodeId: id, NodeInfo: nodeInfo, XmlUrl: temp.xmlUrl
public ActionResult OperateTreeNode(string modeType, string _modeType, string nodeId, string nodeInfo, string xmlUrl)
{
using (RRDLEntities db = new RRDLEntities())
{
Tree tree = new Tree();
TreeNode treeNode = null;
switch (modeType)
{
case "rename":
string id = nodeId;
string name = nodeInfo;
treeNode = tree.GetTreeNodeById(Int32.Parse(id));
treeNode.Title = name;
tree.UpdateTreeNode(treeNode);
returnStr = "ok&" + treeNode.ParentId;
break;
case "delete":
returnStr = DeleteNode(_modeType, nodeId, xmlUrl);
break;
case "insert":
//List<NodeInfo> nodeList = this.GetListFromJson(nodeInfo);
//returnStr = this.InserNode(_modeType, nodeId, xmlUrl, nodeList);
//bool flag = true;
Tree tree2 = new Tree(db);
List<TreeNode> list = tree2.GetTreeNodeChild(Int32.Parse(nodeId));
//for (int i = 0; i < list.Count;i++ )
//{
// if(list[i].Ariticle != null){
// flag = false;
// }
//}
//if (flag)
//{
treeNode = new TreeNode(Int32.Parse(nodeId), "新建节点");
tree.AddTreeNode(treeNode);
returnStr = "ok";
//}
//else {
// returnStr = "该节点下存在文章,不能添加文件夹!";
//}
break;
}
return Content(returnStr);
}
}
示例2: DeleteNode
//The Function Bllew is Added By ZHAOs ,2013年11月14日10:02:13,used to Delete A TreeNode in 目录树管理
public string DeleteNode(string _modeType, string nodeId, string xmlUrl) {
// _modeType = "deleteFolder" ,modeId = "6" ,xmlUrl = "" 传入的参数大致形式如此
Tree tree = new Tree();
TreeNode treeNode = tree.GetTreeNodeById(Convert.ToInt32(nodeId));
string returnStr = "";
/*
如果这个节点是叶子节点
如果是空文件夹 --文件夹(ariticleID为空且isLeaf属性为True),为空文件夹 ===> 可删除
如果是知识 --不能删除知识 (此时 ariticleID属性不为NULL 且 idLeaf属性为 True即是)
如果这个节点不是叶子节点(即非空文件夹,里面可能有知识或者 为空不为空的 文件夹)(ariticleID为空且isLeaf属性为false)====> 不能删除
PS:但是这里不显示知识,所以只可能有 叶子节点文件夹 和 非叶子节点文件夹。
* 叶子节点文件夹内部一定没有知识,可以直接删除 ===>有知识的情况 以后版本考虑
* 非叶子节点文件夹内容一定有文件夹或知识,不能删除。
* 逻辑较简单。
* 只是只能从叶子节点删起
* PS:如果一个父节点其下的所有子节点都被删除,则该父节点的IsLeaf属性变为True
*/
if (treeNode.IsLeaf == true)
{
//如果是根目录
if (treeNode.ParentId == null)
{
returnStr = "根目录不可删除!";
}
else {//若果其父节点下只有这一个子节点,则删除此子节点并把父节点isLeaf属性设为True
TreeNode parentNode = tree.GetTreeNodeById(Convert.ToInt32(treeNode.ParentId));
List<TreeNode> parentChildList = tree.GetTreeNodeChild(Convert.ToInt32(treeNode.ParentId));
if (parentChildList.Count == 1)
{
parentNode.IsLeaf = true;
}
tree.UpdateTreeNode(parentNode);//改变父节点isLeaf属性
tree.Drop(treeNode);//删除子节点
returnStr = "ok";
}
}
else {
returnStr = "该节点下存在子文件夹或知识,不能删除!";
}
return returnStr;
}
示例3: getTreePath
//获取树的路径
public string getTreePath(string treeNode) {
Tree tree = new Tree();
TreeNode tn = tree.GetTreeNodeById(Int32.Parse(treeNode));
List<TreeNode> list = tree.GetTreeNodePath(tn);
string result = "";
for (int i = list.Count-1; i >= 0 ;i-- )
{
result = result + list[i].Title + "TreeSplit";
}
return result;
}
示例4: GetAriticleByTreeNodeId
/// <summary>
/// 通过TreeNodeId获取Ariticle
/// </summary>
/// <param name="_modeType"></param>
/// <param name="_nodeId"></param>
/// <param name="_xmlUrl"></param>
/// <param name="_nodeInfo"></param>
/// <returns></returns>
public ActionResult GetAriticleByTreeNodeId(string treeNodeId,string userId)
{
using (RRDLEntities db = new RRDLEntities())
{
Tree tree = new Tree(db);
Ariticle ariticle = tree.GetTreeNodeById(Int32.Parse(treeNodeId)).Ariticle;
PraiseRepository pr = new PraiseRepository();
//如果是叶子节点,传递知识内容到前台
if (ariticle != null)
{
AriticleViewModel avm = new AriticleViewModel(ariticle);
UserService us = new UserService();
User author = us.FindById(ariticle.UserId);
avm.author = author.NickName;
string time1 = ariticle.Createtime.ToLongDateString();
string time2 = ariticle.Createtime.ToLongTimeString();
avm.Createtime = time1 + " " + time2;
//avm.PraiseCount = pr.FindByAriticleID(ariticle.Id).PraiseCount;
avm.Id = ariticle.Id;
AriticleService ars = new AriticleService();
string isShow = "";
if(userId == "vistor"){
userId = null;
}
if (ars.GetAriticleVisibilityByUser(ariticle.Id, userId))
{
bool falg = ars.GetAriticleVisibilityByUser(ariticle.Id, userId);
isShow = "true";
}
else
{
bool falg = ars.GetAriticleVisibilityByUser(ariticle.Id, userId);
isShow = "false";
}
User user = us.FindById(userId);
if(user!=null && user.ContentGroupId == 2){
isShow = "true";
}
string result = JsonConvert.SerializeObject(avm);
result = result + "ThisAriticleIsShowForThisUser" + isShow;
return Content(result);
}
else
{
return Content("NotLeaf");
}
}
}
示例5: ReadTreeNodes
public List<ClassifyTreeNodes> ReadTreeNodes(List<ClassifyTreeNodes> treeNodes, int? id)
{
Tree tree = new Tree();
List<TreeNode> newTreeNodes = tree.GetParentsTreeNodes(id);
List<ClassifyTreeNodes> treeNodeLists = new List<ClassifyTreeNodes>();
for (int i = 0; i < newTreeNodes.Count; i++)
{
ClassifyTreeNodes treeNode = new ClassifyTreeNodes();
treeNode.Title = newTreeNodes[i].Title;
//treeNode.AriticleId = newTreeNodes[i].Ariticle.Id;
treeNode.Id = newTreeNodes[i].Id;
treeNode.ParentId = newTreeNodes[i].ParentId;
treeNode.IsLeaf = newTreeNodes[i].IsLeaf;
if (treeNode.ParentId == null) {
treeNodes.Add(treeNode);
treeNodeLists.Add(treeNode);
}
//if (treeNode.IsLeaf == false)
//{
// ReadTreeNodes(treeNodes, treeNode.Id);
//}
}
for (int j = 0; j < treeNodes.Count; j++)
{
List<TreeNode> tns = new List<TreeNode>();
tns = tree.GetTreeNodeChild(Int32.Parse(treeNodes[j].Id.ToString()));
for (int k = 0; k < tns.Count; k++) {
TreeNode treeNode = tree.GetTreeNodeById(Int32.Parse(tns[k].Id.ToString()));
ClassifyTreeNodes classifyTreeNodes = new ClassifyTreeNodes();
classifyTreeNodes.Id = treeNode.Id;
classifyTreeNodes.IsLeaf = treeNode.IsLeaf;
classifyTreeNodes.ParentId = treeNode.ParentId;
classifyTreeNodes.Title = treeNode.Title;
treeNodeLists.Add(classifyTreeNodes);
}
}
return treeNodeLists;
}