本文整理汇总了C#中Square.getNeighborInformation方法的典型用法代码示例。如果您正苦于以下问题：C# Square.getNeighborInformation方法的具体用法？C# Square.getNeighborInformation怎么用？C# Square.getNeighborInformation使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Square的用法示例。
在下文中一共展示了Square.getNeighborInformation方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: calculateIndexOfNeighbors
//nsew
public Dictionary<string, int> calculateIndexOfNeighbors(Square square)
{
int index = square.getIndex();
Dictionary<string, int> neighborIndexes = new Dictionary<string,int>();
Dictionary<string, bool> neighboorBools = square.getNeighborInformation();
if(neighboorBools["north"] == true)
{
neighborIndexes.Add("n", index - width);
}
if (neighboorBools["south"] == true)
{
neighborIndexes.Add("s", index + width);
}
if (neighboorBools["east"] == true)
{
neighborIndexes.Add("e", index + 1);
}
if (neighboorBools["west"] == true)
{
neighborIndexes.Add("w", index - 1);
}
return neighborIndexes;
}示例2: calculateIndexOfNeighbor
public int calculateIndexOfNeighbor(Square square, String orientation)
{
int index = square.getIndex();
Dictionary<string, bool> neighboorBools = square.getNeighborInformation();
if (orientation == "north")
{
return (index - width);
}
else if (orientation == "south")
{
return (index + width);
}
else if (orientation == "east")
{
return (index + 1);
}
else if (orientation == "west")
{
return (index - 1);
}
return index;
}