本文整理汇总了C#中ResourceAttributes.GetType方法的典型用法代码示例。如果您正苦于以下问题:C# ResourceAttributes.GetType方法的具体用法?C# ResourceAttributes.GetType怎么用?C# ResourceAttributes.GetType使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ResourceAttributes
的用法示例。
在下文中一共展示了ResourceAttributes.GetType方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: TransferValue
/// <summary>
/// <para>
/// This method allows a generalized implementation of transfering
/// a value from a
/// <see cref="ResourceBuilder.ResourceAttributes"/>
/// to a
/// <see cref="MediaResource"/>
/// object.
/// </para>
///
/// <para>
/// Classes derived from the
/// <see cref="ResourceBuilder.ResourceAttributes"/>
/// class have fields, with names that match against fields in a
/// <see cref="MediaResource"/>
/// object.
/// </para>
/// </summary>
/// <param name="attribName">name of the attribute to transfer</param>
/// <param name="res">The
/// <see cref="MediaResource"/>
/// object to transfer to.
/// </param>
/// <param name="attribs">
/// The
/// <see cref="ResourceBuilder.ResourceAttributes"/>
/// object to transfer from.
/// </param>
private static void TransferValue(string attribName, MediaResource res, ResourceAttributes attribs)
{
object val = null;
System.Type type = attribs.GetType();
FieldInfo info = type.GetField(attribName);
if (info != null)
{
val = info.GetValue(attribs);
if (val != null)
{
IValueType ivt = val as IValueType;
bool ok = true;
if (ivt != null)
{
ok = ivt.IsValid;
}
if (ok)
{
//res.m_Attributes[attribName] = val;
res[attribName] = val;
}
}
}
}