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C# ResourceAttributes.GetType方法代码示例

本文整理汇总了C#中ResourceAttributes.GetType方法的典型用法代码示例。如果您正苦于以下问题:C# ResourceAttributes.GetType方法的具体用法?C# ResourceAttributes.GetType怎么用?C# ResourceAttributes.GetType使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在ResourceAttributes的用法示例。


在下文中一共展示了ResourceAttributes.GetType方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: TransferValue

		/// <summary>
		/// <para>
		/// This method allows a generalized implementation of transfering
		/// a value from a 
		/// <see cref="ResourceBuilder.ResourceAttributes"/>
		/// to a
		/// <see cref="MediaResource"/>
		/// object. 
		/// </para>
		/// 
		/// <para>
		/// Classes derived from the
		/// <see cref="ResourceBuilder.ResourceAttributes"/>
		/// class have fields, with names that match against fields in a 
		/// <see cref="MediaResource"/>
		/// object. 
		/// </para>
		/// </summary>
		/// <param name="attribName">name of the attribute to transfer</param>
		/// <param name="res">The
		/// <see cref="MediaResource"/>
		/// object to transfer to.
		/// </param>
		/// <param name="attribs">
		/// The
		/// <see cref="ResourceBuilder.ResourceAttributes"/>
		/// object to transfer from.
		/// </param>
		private static void TransferValue(string attribName, MediaResource res, ResourceAttributes attribs)
		{
			object val = null;
			
			System.Type type = attribs.GetType();
			FieldInfo info = type.GetField(attribName);
			if (info != null)
			{
				val = info.GetValue(attribs);

				if (val != null)
				{
					IValueType ivt = val as IValueType;

					bool ok = true;
					if (ivt != null)
					{
						ok = ivt.IsValid;
					}
					if (ok)
					{
						//res.m_Attributes[attribName] = val;
						res[attribName] = val;
					}
				}
			}
		}
开发者ID:Scannow,项目名称:SWYH,代码行数:55,代码来源:ResourceBuilder.cs


注:本文中的ResourceAttributes.GetType方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。