本文整理汇总了C#中Histogram.Accumulate方法的典型用法代码示例。如果您正苦于以下问题：C# Histogram.Accumulate方法的具体用法？C# Histogram.Accumulate怎么用？C# Histogram.Accumulate使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Histogram的用法示例。
在下文中一共展示了Histogram.Accumulate方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: GenerateHistograms
/// <summary>
/// Generate histograms for the image. One histogram is generated for each color channel.
/// You will need to call the Refresh function to do the painting afterward.
/// </summary>
/// <param name="image">The image to retrieve histogram from</param>
/// <param name="numberOfBins">The number of bins for each histogram</param>
public void GenerateHistograms(IImage image, int numberOfBins)
{
IImage[] channels = image.Split();
Type imageType = Toolbox.GetBaseType(image.GetType(), "Image`2");
IColor typeOfColor = Activator.CreateInstance(imageType.GetGenericArguments()[0]) as IColor;
String[] channelNames = Reflection.ReflectColorType.GetNamesOfChannels(typeOfColor);
System.Drawing.Color[] colors = Reflection.ReflectColorType.GetDisplayColorOfChannels(typeOfColor);
float minVal, maxVal;
#region Get the maximum and minimum color intensity values
System.Type typeOfDepth = imageType.GetGenericArguments()[1];
if (typeOfDepth == typeof(Byte))
{
minVal = 0.0f;
maxVal = 256.0f;
}
else
{
#region obtain the maximum and minimum color value
double[] minValues, maxValues;
System.Drawing.Point[] minLocations, maxLocations;
image.MinMax(out minValues, out maxValues, out minLocations, out maxLocations);
double min = minValues[0], max = maxValues[0];
for (int i = 1; i < minValues.Length; i++)
{
if (minValues[i] < min) min = minValues[i];
if (maxValues[i] > max) max = maxValues[i];
}
#endregion
minVal = (float)min;
maxVal = (float)max;
}
#endregion
for (int i = 0; i < channels.Length; i++)
using (Histogram hist = new Histogram(numberOfBins, new RangeF(minVal, maxVal)))
{
hist.Accumulate(new IImage[1] { channels[i] });
AddHistogram(channelNames[i], colors[i], hist);
}
}