本文整理汇总了C#中Color.Contains方法的典型用法代码示例。如果您正苦于以下问题:C# Color.Contains方法的具体用法?C# Color.Contains怎么用?C# Color.Contains使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Color
的用法示例。
在下文中一共展示了Color.Contains方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: Combine
public static Color Combine(this Color color, Color otherColor)
{
// primary combinations
if ((color == Red && otherColor == Blue) || (color == Blue && otherColor == Red))
return Purple;
if ((color == Blue && otherColor == Yellow) || (color == Yellow && otherColor == Blue))
return Green;
if ((color == Red && otherColor == Yellow) || (color == Yellow && otherColor == Red))
return Orange;
// redundant color combinations
if (color.Contains(otherColor))
return color;
if (otherColor.Contains(color))
return otherColor;
#if DEBUG
Console.WriteLine(String.Format("Possibly unsupported color combination: {0} and {1}", color.ToString(), otherColor.ToString()));
#endif
return Black;
}
示例2: Generate
public void Generate()
{
// Highly experimental
// Componer paleta
Color[] tpalette = new Color[paleta_extra.Length];//[256];
int i = 0;
for (int x = 0; x < width; x++)
{
for (int y = 0; y < height; y++)
{
Color color = bitmap.GetPixel(x, y);
if (!tpalette.Contains(color))
{
tpalette.SetValue(color, i);
i++;
}
}
}
// Pasar la paleta a 555Color
palette = new _555Color[tpalette.Length];
for (int j = 0; j < tpalette.Length; j++)
{
//palette.SetValue(new _555Color(tpalette[j]), j);
palette.SetValue(paleta_extra[j], j);
}
// Generar los tiles numericos
int total = width * height;
total_tiles = (ushort)(total / 64);
int current = 0;
int extra_x = 0;
int extra_y = 0;
// array con todos los bytes de los tiles
tiles = new byte[width * height];
while (current < total)
{
for (int y = 0; y < 8; y++)
{
for (int x = 0; x < 8; x++)
{
Color color = bitmap.GetPixel(x + extra_x, y + extra_y);
_555Color color2 = new _555Color(color);
for (int j = 0; j < palette.Length; j++)
{
if (palette[j].Int16 == color2.Int16)
{
// Guardar la posicion del color
tiles.SetValue((byte)j, current);
break;
}
else { tiles.SetValue((byte)0, current); }
}
current++;
}
}
extra_x += 8;
if (extra_x >= width)
{
extra_x = 0;
extra_y += 8;
}
}
}
示例3: button1_Click
private void button1_Click(object sender, EventArgs e)
{
if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
bmp = (Bitmap)Bitmap.FromFile(openFileDialog1.FileName);
pictureBox1.Height = bmp.Height;
pictureBox1.Width = bmp.Width;
pictureBox1.Image = bmp;
if (pictureBox1.Height > 240)
{
this.Height = pictureBox1.Top + pictureBox1.Height + 60;
}
this.Width = pictureBox1.Left + pictureBox1.Width + 40;
for (int row = 0; row < bmp.Height; row++)
{
int coloursThisRow = 0;
Color[] rowColors = new Color[0];
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
thisStitch = bmp.GetPixel(stitch, row);
if (!colors.Contains(thisStitch))
{
Array.Resize(ref colors, colors.Length + 1);
colors[colors.Length - 1] = thisStitch;
}
if (!rowColors.Contains(thisStitch))
{
Array.Resize(ref rowColors, rowColors.Length + 1);
rowColors[rowColors.Length - 1] = thisStitch;
coloursThisRow++;
}
if (coloursThisRow > MaxColoursPerRow)
{
MaxColoursPerRow = coloursThisRow;
}
}
}
for (int i = 0; i < colors.Length; i++)
{
Array.Resize(ref colorButtons, colorButtons.Length + 1);
colorButtons[colorButtons.Length - 1] = new Button();
colorButtons[colorButtons.Length - 1].Left = 10;
colorButtons[colorButtons.Length - 1].Top = i * (colorButtons[colorButtons.Length - 1].Height + 3) + 60;
colorButtons[colorButtons.Length - 1].BackColor = colors[i];
this.Controls.Add(colorButtons[colorButtons.Length - 1]);
Array.Resize(ref colorNumber, colorNumber.Length + 1);
colorNumber[colorNumber.Length - 1] = new TextBox();
colorNumber[colorNumber.Length - 1].Left = colorButtons[colorButtons.Length - 1].Left + colorButtons[colorButtons.Length - 1].Width + 10;
colorNumber[colorNumber.Length - 1].Top = colorButtons[colorButtons.Length - 1].Top;
colorNumber[colorNumber.Length - 1].Text = (i + 1).ToString();
this.Controls.Add(colorNumber[colorNumber.Length - 1]);
}
label1.Text = "Max colours per row: " + MaxColoursPerRow.ToString();
label2.Text = "Rows: " + bmp.Height.ToString();
label3.Text = "Stitches: " + bmp.Width.ToString();
// button1.Text = colors.Length.ToString();
if (MaxColoursPerRow > 2)
{
buttonConvert.Visible = true;
button1.Visible = false;
}
else
{
buttonConvert.Visible = false;
button1.Visible = true;
}
}
}
示例4: button2_Click
private void button2_Click(object sender, EventArgs e)
{
int colour;
int i;
output = new Byte[bmp.Height, bmp.Width];
for (int row = 0; row < bmp.Height; row++)
{
Color[] rowColors = new Color[MaxColoursPerRow];
int colorCount = 0;
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
thisStitch = bmp.GetPixel(stitch, row);
if (!rowColors.Contains(thisStitch))
{
rowColors[colorCount++] = thisStitch;
}
}
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
thisStitch = bmp.GetPixel(stitch, row);
for (i = 0; i < colors.Length; i++)
{
if (thisStitch == colors[i])
{
colour = Convert.ToInt32(colorNumber[i].Text);
output[row, stitch] = (Byte)colour;
break;
}
}
}
}
// Array 'output' now contains one byte per pixel (stitch), with number representing colour of yarn to use. Let's dump it to a file for reference.
System.IO.StreamWriter stream = new System.IO.StreamWriter("C:\\Knitulator\\Frontproof.txt");
for (int row = 0; row < bmp.Height; row++)
{
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
stream.Write(output[row, stitch].ToString());
}
stream.WriteLine();
}
stream.Close();
// Now lets create a Multicolour pattern, where each row contains a boolean indicating do or don't use the colour.
// A separate array is required, for each row to indicate which colour to use.
//TOD: Make sure patternRowColour is multiple of 2 as colours are stored as nibbles
Byte[] patternRowColour = new Byte[bmp.Height * MaxColoursPerRow]; // Array to hold colour of yarn to use on each Multicolour row
int widthInBits = (int)(8 * Math.Round(bmp.Width / (double)8, MidpointRounding.AwayFromZero)); // must be multiple of 8 bits
Byte[,] pattern = new Byte[bmp.Height * MaxColoursPerRow, widthInBits]; // Array to hold pattern data = 1 byte represents 8 stitches
System.IO.StreamWriter stream2 = new System.IO.StreamWriter("C:\\Knitulator\\Frontmc.txt");
int n = bmp.Height * MaxColoursPerRow;
stream2.WriteLine("Row : Disp : Col : Row Pattern");
for (int row = 0; row < bmp.Height; row++)
{
// Work out which colours to knit:
Byte[] rowColours = new Byte[MaxColoursPerRow];
int colourCount = 0;
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
if (!rowColours.Contains(output[row, stitch]))
{
rowColours[colourCount++] = output[row, stitch];
}
}
if (rowColours[1] == 0)
{
rowColours[1] = 8;
rowColours[2] = 9;
}
if (rowColours[2] == 0)
{
rowColours[2] = 9;
}
for (i = 0; i < MaxColoursPerRow; i++)
{
stream2.Write((bmp.Height - row).ToString("D3") + " : ");
stream2.Write(n.ToString("D3") + " : ");
n--;
//.........这里部分代码省略.........
示例5: button1_Click_1
private void button1_Click_1(object sender, EventArgs e)
{
int colour;
int i;
output = new Byte[bmp.Height, bmp.Width];
for (int row = 0; row < bmp.Height; row++)
{
Color[] rowColors = new Color[MaxColoursPerRow];
int colorCount = 0;
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
thisStitch = bmp.GetPixel(stitch, row);
if (!rowColors.Contains(thisStitch))
{
rowColors[colorCount++] = thisStitch;
}
}
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
thisStitch = bmp.GetPixel(stitch, row);
for (i = 0; i < colors.Length; i++)
{
if (thisStitch == colors[i])
{
colour = Convert.ToInt32(colorNumber[i].Text);
output[row, stitch] = (Byte)colour;
break;
}
}
}
}
// Array 'output' now contains one byte per pixel (stitch), with number representing colour of yarn to use. Let's dump it to a file for reference.
System.IO.StreamWriter stream = new System.IO.StreamWriter("C:\\Knitulator\\proof.txt");
for (int row = 0; row < bmp.Height; row++)
{
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
stream.Write(output[row, stitch].ToString());
}
stream.WriteLine();
}
stream.Close();
// Now lets create a 2 colour pattern, where each row contains a boolean indicating do or don't use the contrast yarn.
int widthInBits = (int)(8 * Math.Round(bmp.Width / (double)8, MidpointRounding.AwayFromZero)); // must be multiple of 8 bits
Byte[,] pattern = new Byte[bmp.Height, widthInBits]; // Array to hold pattern data = 1 byte represents 8 stitches
System.IO.StreamWriter stream2 = new System.IO.StreamWriter("C:\\Knitulator\\2col.txt");
int n = bmp.Height;
stream2.WriteLine("Row : Row Pattern");
for (int row = 0; row < bmp.Height; row++)
{
stream2.Write((bmp.Height - row).ToString("D3") + " : ");
n--;
for (int stitch = 0; stitch < bmp.Width; stitch++)
{
if (output[row, stitch] == 2)
{
stream2.Write("X");
pattern[row, stitch] = 1;
}
else
{
stream2.Write(".");
pattern[row, stitch] = 0;
}
}
stream2.WriteLine();
}
stream2.Close();
// Now create binary array in brother format, 1 bit per pixel
Byte[,] patternOut = new Byte[bmp.Height, widthInBits / 8];
for (int row = 0; row < bmp.Height; row++)
{
Byte bit = 0;
for (int stitch = 0; stitch < widthInBits; stitch++)
{
bit = (Byte)(stitch & 0x07);
bit = (Byte)(0x80 >> bit);
patternOut[row, stitch / 8] = (Byte)(patternOut[row, stitch / 8] | ((2 ^ bit) * pattern[row, stitch]));
//.........这里部分代码省略.........