本文整理汇总了C++中ogre::Quaternion::ToAxes方法的典型用法代码示例。如果您正苦于以下问题：C++ Quaternion::ToAxes方法的具体用法？C++ Quaternion::ToAxes怎么用？C++ Quaternion::ToAxes使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ogre::Quaternion的用法示例。
在下文中一共展示了Quaternion::ToAxes方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: getOrientedBox
//------------------------------------------------------------------------------------------------
bool AnimatedMeshToShapeConverter::getOrientedBox(unsigned char bone,
const Ogre::Vector3 &bonePosition,
const Ogre::Quaternion &boneOrientation,
Ogre::Vector3 &box_afExtent,
Ogre::Vector3 *box_akAxis,
Ogre::Vector3 &box_kCenter)
{
unsigned int vertex_count;
Ogre::Vector3 *vertices;
if (!getBoneVertices(bone, vertex_count, vertices, bonePosition))
{
return false;
}
box_kCenter = Ogre::Vector3::ZERO;
{
for (unsigned int c = 0 ; c < vertex_count; ++c)
{
box_kCenter += vertices[c];
}
const Ogre::Real invVertexCount = 1.0 / vertex_count;
box_kCenter *= invVertexCount;
}
Ogre::Quaternion orient = boneOrientation;
orient.ToAxes(box_akAxis);
// Let C be the box center and let U0, U1, and U2 be the box axes. Each
// input point is of the form X = C + y0*U0 + y1*U1 + y2*U2. The
// following code computes min(y0), max(y0), min(y1), max(y1), min(y2),
// and max(y2). The box center is then adjusted to be
// C' = C + 0.5*(min(y0)+max(y0))*U0 + 0.5*(min(y1)+max(y1))*U1 +
// 0.5*(min(y2)+max(y2))*U2
Ogre::Vector3 kDiff (vertices[1] - box_kCenter);
Ogre::Real fY0Min = kDiff.dotProduct(box_akAxis[0]), fY0Max = fY0Min;
Ogre::Real fY1Min = kDiff.dotProduct(box_akAxis[1]), fY1Max = fY1Min;
Ogre::Real fY2Min = kDiff.dotProduct(box_akAxis[2]), fY2Max = fY2Min;
for (unsigned int i = 2; i < vertex_count; ++i)
{
kDiff = vertices[i] - box_kCenter;
const Ogre::Real fY0 = kDiff.dotProduct(box_akAxis[0]);
if (fY0 < fY0Min)
{
fY0Min = fY0;
}
else
if (fY0 > fY0Max)
{
fY0Max = fY0;
}
const Ogre::Real fY1 = kDiff.dotProduct(box_akAxis[1]);
if (fY1 < fY1Min)
{
fY1Min = fY1;
}
else
if (fY1 > fY1Max)
{
fY1Max = fY1;
}
const Ogre::Real fY2 = kDiff.dotProduct(box_akAxis[2]);
if (fY2 < fY2Min)
{
fY2Min = fY2;
}
else
if (fY2 > fY2Max)
{
fY2Max = fY2;
}
}
box_afExtent.x = (0.5f) * (fY0Max - fY0Min);
box_afExtent.y = (0.5f) * (fY1Max - fY1Min);
box_afExtent.z = (0.5f) * (fY2Max - fY2Min);
box_kCenter += (0.5f * (fY0Max+fY0Min)) * box_akAxis[0] +
(0.5f * (fY1Max+fY1Min)) * box_akAxis[1] +
(0.5f * (fY2Max+fY2Min)) * box_akAxis[2];
box_afExtent *= 2.0f;
return true;
}