本文整理汇总了C++中pANTLR3_BASE_TREE::getText方法的典型用法代码示例。如果您正苦于以下问题:C++ pANTLR3_BASE_TREE::getText方法的具体用法?C++ pANTLR3_BASE_TREE::getText怎么用?C++ pANTLR3_BASE_TREE::getText使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类pANTLR3_BASE_TREE
的用法示例。
在下文中一共展示了pANTLR3_BASE_TREE::getText方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: dumpNode
void SCsTranslator::dumpNode(pANTLR3_BASE_TREE node, std::ofstream &stream)
{
StringStream ss;
ss << node;
String s_root = ss.str().substr(3);
pANTLR3_COMMON_TOKEN tok = node->getToken(node);
if (tok)
{
stream << s_root << " [shape=box];" << std::endl;
String label((const char*) node->getText(node)->chars);
std::replace(label.begin(), label.end(), '"', '\'');
stream << s_root << " [label=\"" << label << "\"];" << std::endl;
}
else
stream << s_root << " [shape=circle];" << std::endl;
uint32 n = node->getChildCount(node);
for (uint32 i = 0; i < n; ++i)
{
pANTLR3_BASE_TREE child = (pANTLR3_BASE_TREE) node->getChild(node, i);
StringStream s1;
s1 << child;
stream << s_root << " -> " << s1.str().substr(3) << ";" << std::endl;
dumpNode(child, stream);
}
}
示例2: dumpTree
std::string MySQLRecognitionBase::dumpTree(pANTLR3_UINT8 *tokenNames, pANTLR3_BASE_TREE tree, const std::string &indentation)
{
std::string result;
ANTLR3_UINT32 char_pos = tree->getCharPositionInLine(tree);
ANTLR3_UINT32 line = tree->getLine(tree);
pANTLR3_STRING token_text = tree->getText(tree);
pANTLR3_COMMON_TOKEN token = tree->getToken(tree);
const char* utf8 = (const char*)token_text->chars;
if (token != NULL)
{
ANTLR3_UINT32 token_type = token->getType(token);
pANTLR3_UINT8 token_name;
if (token_type == EOF)
token_name = (pANTLR3_UINT8)"EOF";
else
token_name = tokenNames[token_type];
#ifdef ANTLR3_USE_64BIT
result = base::strfmt("%s(line: %i, offset: %i, length: %" PRId64 ", index: %" PRId64 ", %s[%i]) %s\n",
indentation.c_str(), line, char_pos, token->stop - token->start + 1, token->index, token_name,
token_type, utf8);
#else
result = base::strfmt("%s(line: %i, offset: %i, length: %i, index: %i, %s[%i]) %s\n",
indentation.c_str(), line, char_pos, token->stop - token->start + 1, token->index, token_name,
token_type, utf8);
#endif
}
else
{
result = base::strfmt("%s(line: %i, offset: %i, nil) %s\n", indentation.c_str(), line, char_pos, utf8);
}
for (ANTLR3_UINT32 index = 0; index < tree->getChildCount(tree); index++)
{
pANTLR3_BASE_TREE child = (pANTLR3_BASE_TREE)tree->getChild(tree, index);
std::string child_text = dumpTree(tokenNames, child, indentation + "\t");
result += child_text;
}
return result;
}
示例3:
static pANTLR3_STRING
getText (pANTLR3_BASE_TREE_ADAPTOR adaptor, pANTLR3_BASE_TREE t)
{
return t->getText(t);
}
示例4: token_text
/**
* Returns the text of the given node. The result depends on the type of the node. If it represents
* a quoted text entity then two consecutive quote chars are replaced by a single one and if
* escape sequence parsing is not switched off (as per sql mode) then such sequences are handled too.
*/
std::string MySQLRecognitionBase::token_text(pANTLR3_BASE_TREE node, bool keepQuotes)
{
pANTLR3_STRING text = node->getText(node);
if (text == NULL)
return "";
std::string chars;
pANTLR3_COMMON_TOKEN token = node->getToken(node);
ANTLR3_UINT32 type = (token != NULL) ? token->type : ANTLR3_TOKEN_INVALID;
if (type == STRING_TOKEN)
{
// STRING is the grouping subtree for multiple consecutive string literals, which
// must be concatenated.
for (ANTLR3_UINT32 index = 0; index < node->getChildCount(node); index++)
{
pANTLR3_BASE_TREE child = (pANTLR3_BASE_TREE)node->getChild(node, index);
chars += token_text(child, keepQuotes);
}
return chars;
}
chars = (const char*)text->chars;
std::string quote_char;
switch (type)
{
case BACK_TICK_QUOTED_ID:
quote_char = "`";
break;
case SINGLE_QUOTED_TEXT:
quote_char = "'";
break;
case DOUBLE_QUOTED_TEXT:
quote_char = "\"";
break;
default:
return chars;
}
// First unquote then handle escape squences and double quotes.
if (chars.size() < 3)
{
if (keepQuotes)
return chars;
return ""; // Also handles an invalid single quote char gracefully.
}
// Need to unquote even if keepQuotes is true to avoid trouble with replacing the outer quotes.
// Add them back below.
chars = base::unquote(chars);
if ((d->_sql_mode & SQL_MODE_NO_BACKSLASH_ESCAPES) == 0)
chars = base::unescape_sql_string(chars, quote_char[0]);
else
if (token->user1 > 0)
{
// The field user1 is set by the parser to the number of quote char pairs it found.
// So we can use it to shortcut our handling here.
base::replace(chars, quote_char + quote_char, quote_char);
}
if (keepQuotes)
return quote_char + chars + quote_char;
return chars;
}
示例5: if
/// Delete children from start to stop and replace with t even if t is
/// a list (nil-root tree). Num of children can increase or decrease.
/// For huge child lists, inserting children can force walking rest of
/// children to set their child index; could be slow.
///
static void
replaceChildren (pANTLR3_BASE_TREE parent, ANTLR3_INT32 startChildIndex, ANTLR3_INT32 stopChildIndex, pANTLR3_BASE_TREE newTree)
{
ANTLR3_INT32 replacingHowMany; // How many nodes will go away
ANTLR3_INT32 replacingWithHowMany; // How many nodes will replace them
ANTLR3_INT32 numNewChildren; // Tracking variable
ANTLR3_INT32 delta; // Difference in new vs existing count
ANTLR3_INT32 i;
ANTLR3_INT32 j;
pANTLR3_VECTOR newChildren; // Iterator for whatever we are going to add in
ANTLR3_BOOLEAN freeNewChildren; // Whether we created the iterator locally or reused it
if (parent->children == NULL)
{
ANTLR3_FPRINTF(stderr, "replaceChildren call: Indexes are invalid; no children in list for %s", parent->getText(parent)->chars);
return;
}
// Either use the existing list of children in the supplied nil node, or build a vector of the
// tree we were given if it is not a nil node, then we treat both situations exactly the same
//
if (newTree->isNilNode(newTree))
{
newChildren = newTree->children;
freeNewChildren = ANTLR3_FALSE; // We must NO free this memory
}
else
{
newChildren = antlr3VectorNew(1);
if (newChildren == NULL)
{
ANTLR3_FPRINTF(stderr, "replaceChildren: out of memory!!");
exit(1);
}
newChildren->add(newChildren, (void *)newTree, NULL);
freeNewChildren = ANTLR3_TRUE; // We must free this memory
}
// Initialize
//
replacingHowMany = stopChildIndex - startChildIndex + 1;
replacingWithHowMany = newChildren->size(newChildren);
delta = replacingHowMany - replacingWithHowMany;
numNewChildren = newChildren->size(newChildren);
// If it is the same number of nodes, then do a direct replacement
//
if (delta == 0)
{
pANTLR3_BASE_TREE child;
// Same number of nodes
//
j = 0;
for (i = startChildIndex; i <= stopChildIndex; i++)
{
child = (pANTLR3_BASE_TREE) newChildren->get(newChildren, j);
parent->children->set(parent->children, i, child, NULL, ANTLR3_FALSE);
child->setParent(child, parent);
child->setChildIndex(child, i);
}
}
else if (delta > 0)
{
ANTLR3_UINT32 indexToDelete;
// Less nodes than there were before
// reuse what we have then delete the rest
//
for (j = 0; j < numNewChildren; j++)
{
parent->children->set(parent->children, startChildIndex + j, newChildren->get(newChildren, j), NULL, ANTLR3_FALSE);
}
// We just delete the same index position until done
//
indexToDelete = startChildIndex + numNewChildren;
for (j = indexToDelete; j <= (ANTLR3_INT32)stopChildIndex; j++)
{
parent->children->remove(parent->children, indexToDelete);
}
parent->freshenPACIndexes(parent, startChildIndex);
}
else
{
ANTLR3_UINT32 numToInsert;
// More nodes than there were before
// Use what we can, then start adding
//
//.........这里部分代码省略.........