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C++ pANTLR3_BASE_TREE类代码示例

本文整理汇总了C++中pANTLR3_BASE_TREE的典型用法代码示例。如果您正苦于以下问题:C++ pANTLR3_BASE_TREE类的具体用法?C++ pANTLR3_BASE_TREE怎么用?C++ pANTLR3_BASE_TREE使用的例子?那么恭喜您, 这里精选的类代码示例或许可以为您提供帮助。


在下文中一共展示了pANTLR3_BASE_TREE类的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: LiteralValueDef

	IntegerLiteralValueDef::IntegerLiteralValueDef(const pANTLR3_BASE_TREE node)
		: LiteralValueDef(INTEGER_LITERAL, node)
	{
		assert(node->getType(node) == N_INT_LITERAL);
		assert(node->getChildCount(node) == 1);

		pANTLR3_BASE_TREE n = (pANTLR3_BASE_TREE) node->getChild(node, 0);

		assert(n->getType(n) == INTL);

		wchar_t* szStr = (wchar_t*) n->getText(n)->chars;
		
		int value;

		try
		{
			value = boost::lexical_cast<int, wchar_t*>(szStr);
		}
		catch (const std::exception&)
		{
			boost::wformat f(L"Invalid integer value: %1% at line %2%");
			f % szStr % node->getLine(node);
			ParserException e(f.str());
			throw e;
		}

		m_IntValue = value;
	}
开发者ID:ernestobad,项目名称:ContainedObjects,代码行数:28,代码来源:IntegerLiteralValueDef.cpp

示例2: assert

void SCsTranslator::processSentenceAssign(pANTLR3_BASE_TREE node)
{
    unsigned int nodesCount = node->getChildCount(node);
    assert(nodesCount == 2);

    pANTLR3_BASE_TREE node_left = (pANTLR3_BASE_TREE)node->getChild(node, 0);
    pANTLR3_BASE_TREE node_right = (pANTLR3_BASE_TREE)node->getChild(node, 1);

    pANTLR3_COMMON_TOKEN tok_left = node_left->getToken(node_left);
    pANTLR3_COMMON_TOKEN tok_right = node_left->getToken(node_right);

    assert(tok_left && tok_right);

    if (tok_left->type != ID_SYSTEM)
    {
        THROW_EXCEPT(Exception::ERR_PARSE,
                     "Unsupported type of tokens at the left side of assignment sentence",
                     mParams.fileName,
                     tok_left->getLine(tok_left));
    }

    if (tok_right->type == ID_SYSTEM)
    {
        mAssignments[GET_NODE_TEXT(node_left)] = GET_NODE_TEXT(node_right);
    }
    else
    {
        String left_idtf = (GET_NODE_TEXT(node_left));
        sElement *el = parseElementTree(node_right, &left_idtf);
    }
}
开发者ID:rusetski-k,项目名称:sc-machine,代码行数:31,代码来源:scs_translator.cpp

示例3: label

void SCsTranslator::dumpNode(pANTLR3_BASE_TREE node, std::ofstream &stream)
{
    StringStream ss;
    ss << node;

    String s_root = ss.str().substr(3);
    pANTLR3_COMMON_TOKEN tok = node->getToken(node);
    if (tok)
    {
        stream << s_root << " [shape=box];" << std::endl;
        String label((const char*) node->getText(node)->chars);
        std::replace(label.begin(), label.end(), '"', '\'');
        stream << s_root << " [label=\"" << label << "\"];" << std::endl;
    }
    else
        stream << s_root << " [shape=circle];" << std::endl;

    uint32 n = node->getChildCount(node);
    for (uint32 i = 0; i < n; ++i)
    {
        pANTLR3_BASE_TREE child = (pANTLR3_BASE_TREE) node->getChild(node, i);
        StringStream s1;
        s1 << child;

        stream << s_root << " -> " << s1.str().substr(3) << ";" << std::endl;
        dumpNode(child, stream);
    }
}
开发者ID:rusetski-k,项目名称:sc-machine,代码行数:28,代码来源:scs_translator.cpp

示例4:

pANTLR3_BASE_TREE
dupTreeTT			(pANTLR3_BASE_TREE_ADAPTOR adaptor, pANTLR3_BASE_TREE t, pANTLR3_BASE_TREE parent)
{
	pANTLR3_BASE_TREE	newTree;
	pANTLR3_BASE_TREE	child;
	pANTLR3_BASE_TREE	newSubTree;
	ANTLR3_UINT32		n;
	ANTLR3_UINT32		i;

	if	(t == NULL)
	{
		return NULL;
	}
	newTree = (pANTLR3_BASE_TREE)t->dupNode(t);

	// Ensure new subtree root has parent/child index set
	//
	adaptor->setChildIndex		(adaptor, newTree, t->getChildIndex(t));
	adaptor->setParent			(adaptor, newTree, parent);
	n = adaptor->getChildCount	(adaptor, t);

	for	(i=0; i < n; i++)
	{
		child = (pANTLR3_BASE_TREE)adaptor->getChild		(adaptor, t, i);
		newSubTree = (pANTLR3_BASE_TREE)adaptor->dupTreeTT	(adaptor, child, t);
		adaptor->addChild				(adaptor, newTree, newSubTree);
	}
	return	newTree;
}
开发者ID:Daniel1892,项目名称:tora,代码行数:29,代码来源:antlr3basetreeadaptor.c

示例5: ASTNode

ActualParamDef::ActualParamDef(const pANTLR3_BASE_TREE node)
    : ASTNode(node)
{
    assert(node->getType(node) == N_ACTUAL_PARAM);
    assert(node->getChildCount(node) == 2);

    pANTLR3_BASE_TREE n;

    {
        // param name
        n = (pANTLR3_BASE_TREE) node->getChild(node, 0);
        assert(n->getType(n) == N_PARAM_NAME);
        assert(n->getChildCount(n) == 1);

        n = (pANTLR3_BASE_TREE) n->getChild(n, 0);

        m_ParamName = (wchar_t*) n->getText(n)->chars;
    }

    {
        // value
        n = (pANTLR3_BASE_TREE) node->getChild(node, 1);
        assert(n->getType(n) == N_VALUE);

        createValueDef(n, m_pValue);
    }
}
开发者ID:ernestobad,项目名称:ContainedObjects,代码行数:27,代码来源:ActualParamDef.cpp

示例6: ValueDef

	ArrayInitValueDef::ArrayInitValueDef(const pANTLR3_BASE_TREE node)
		: ValueDef(ARRAY_INIT, node)
	{
		assert(node->getType(node) == N_ARRAY_INIT_VAL);
		assert(node->getChildCount(node) == 2);

		pANTLR3_BASE_TREE n, c;

		{
			// type
			n = (pANTLR3_BASE_TREE) node->getChild(node, 0);
			assert(n->getType(n) == N_ARRAY_TYPE);
			
			m_pDeclaredType = boost::shared_ptr<Type>(static_cast<Type*>(new ArrayType(n)));
		}

		{
			// array values
			n = (pANTLR3_BASE_TREE) node->getChild(node, 1);
			assert(n->getType(n) == N_ARRAY_VALUES);

			m_Values.clear();

			int childCount = n->getChildCount(n);
			for (int i = 0; i < childCount; i++)
			{
				c = (pANTLR3_BASE_TREE) n->getChild(n, i);

				boost::shared_ptr<ValueDef> pValueDef;
				createValueDef(c, pValueDef);

				m_Values.push_back(pValueDef);
			}
		}
	}
开发者ID:ernestobad,项目名称:ContainedObjects,代码行数:35,代码来源:ArrayInitValueDef.cpp

示例7:

/** Transform ^(nil x) to x 
 */
static	pANTLR3_BASE_TREE	
   rulePostProcessing	(pANTLR3_BASE_TREE_ADAPTOR adaptor, pANTLR3_BASE_TREE root)
{

	if (root != NULL && root->isNil(root) && root->getChildCount(root) == 1)
	{
		root = root->getChild(root, 0);
	}

	return root;
}
开发者ID:UIKit0,项目名称:mclab,代码行数:13,代码来源:antlr3basetreeadaptor.c

示例8: emerson_printAST

pANTLR3_STRING emerson_printAST(pANTLR3_BASE_TREE tree, pANTLR3_UINT8* parserTokenNames)
{
  pANTLR3_STRING  string;
  ANTLR3_UINT32   i;
  ANTLR3_UINT32   n;
  pANTLR3_BASE_TREE   t;


  if(tree->children == NULL || tree->children->size(tree->children) == 0)
  {
      return	tree->toString(tree);
  }

  // THis is how you get a new string. The string is blank

  string = tree->strFactory->newRaw(tree->strFactory);

  if(tree->isNilNode(tree) == ANTLR3_FALSE)
  {
      string->append8	(string, "(");
      pANTLR3_COMMON_TOKEN token = tree->getToken(tree);
      ANTLR3_UINT32 type = token->type;

      string->append(string, (const char*)parserTokenNames[type]);
      string->append8(string, " ");
  }

  if(tree->children != NULL)
  {
      n = tree->children->size(tree->children);
      for	(i = 0; i < n; i++)
      {
          t   = (pANTLR3_BASE_TREE) tree->children->get(tree->children, i);

          if  (i > 0)
          {
              string->append8(string, " ");
          }
          string->appendS(string, emerson_printAST(t,parserTokenNames));
      }
  }

  if(tree->isNilNode(tree) == ANTLR3_FALSE)
  {
      string->append8(string,")");
  }

  return  string;
}
开发者ID:LittleForker,项目名称:sirikata,代码行数:49,代码来源:Util.cpp

示例9:

/** If oldRoot is a nil root, just copy or move the children to newRoot.
 *  If not a nil root, make oldRoot a child of newRoot.
 *
 * \code
 *    old=^(nil a b c), new=r yields ^(r a b c)
 *    old=^(a b c), new=r yields ^(r ^(a b c))
 * \endcode
 *
 *  If newRoot is a nil-rooted single child tree, use the single
 *  child as the new root node.
 *
 * \code
 *    old=^(nil a b c), new=^(nil r) yields ^(r a b c)
 *    old=^(a b c), new=^(nil r) yields ^(r ^(a b c))
 * \endcode
 *
 *  If oldRoot was null, it's ok, just return newRoot (even if isNilNode).
 *
 * \code
 *    old=null, new=r yields r
 *    old=null, new=^(nil r) yields ^(nil r)
 * \endcode
 *
 *  Return newRoot.  Throw an exception if newRoot is not a
 *  simple node or nil root with a single child node--it must be a root
 *  node.  If newRoot is <code>^(nil x)</endcode> return x as newRoot.
 *
 *  Be advised that it's ok for newRoot to point at oldRoot's
 *  children; i.e., you don't have to copy the list.  We are
 *  constructing these nodes so we should have this control for
 *  efficiency.
 */
static	pANTLR3_BASE_TREE	
becomeRoot	(pANTLR3_BASE_TREE_ADAPTOR adaptor, pANTLR3_BASE_TREE newRootTree, pANTLR3_BASE_TREE oldRootTree)
{
	/* Protect against tree rewrites if we are in some sort of error
	 * state, but have tried to recover. In C we can end up with a null pointer
	 * for a tree that was not produced.
	 */
	if	(newRootTree == NULL)
	{
		return	oldRootTree;
	}

	/* root is just the new tree as is if there is no
	 * current root tree.
	 */
	if	(oldRootTree == NULL)
	{
		return	newRootTree;
	}

	/* Produce ^(nil real-node)
	 */
	if	(newRootTree->isNilNode(newRootTree))
	{
		if	(newRootTree->getChildCount(newRootTree) > 1)
		{
			/* TODO: Handle tree exceptions 
			 */
			ANTLR3_FPRINTF(stderr, "More than one node as root! TODO: Create tree exception hndling\n");
			return newRootTree;
		}

		/* The new root is the first child
		 */
		newRootTree = newRootTree->getChild(newRootTree, 0);
	}

	/* Add old root into new root. addChild takes care of the case where oldRoot
	 * is a flat list (nill rooted tree). All children of oldroot are added to
	 * new root.
	 */
	newRootTree->addChild(newRootTree, oldRootTree);

	/* Always returns new root structure
	 */
	return	newRootTree;

}
开发者ID:aslakhellesoy,项目名称:antlr-3,代码行数:80,代码来源:antlr3basetreeadaptor.c

示例10: addChild

/** Add a child to the tree t.  If child is a flat tree (a list), make all
 *  in list children of t. Warning: if t has no children, but child does
 *  and child isNilNode then it is ok to move children to t via
 *  t.children = child.children; i.e., without copying the array.  This
 *  is for construction and I'm not sure it's completely general for
 *  a tree's addChild method to work this way.  Make sure you differentiate
 *  between your tree's addChild and this parser tree construction addChild
 *  if it's not ok to move children to t with a simple assignment.
 */
static	void	
addChild (pANTLR3_BASE_TREE_ADAPTOR adaptor, pANTLR3_BASE_TREE t, pANTLR3_BASE_TREE child)
{
	if	(t != NULL && child != NULL)
	{
		t->addChild(t, child);
	}
}
开发者ID:Daniel1892,项目名称:tora,代码行数:17,代码来源:antlr3basetreeadaptor.c

示例11:

static pANTLR3_STRING
toStringTree	(pANTLR3_BASE_TREE tree)
{
	pANTLR3_STRING  string;
	ANTLR3_UINT32   i;
	ANTLR3_UINT32   n;
	pANTLR3_BASE_TREE   t;

	if	(tree->children == NULL || tree->children->size(tree->children) == 0)
	{
		return	tree->toString(tree);
	}

	/* Need a new string with nothing at all in it.
	*/
	string	= tree->strFactory->newRaw(tree->strFactory);

	if	(tree->isNilNode(tree) == ANTLR3_FALSE)
	{
		string->append8	(string, "(");
		string->appendS	(string, tree->toString(tree));
		string->append8	(string, " ");
	}
	if	(tree->children != NULL)
	{
		n = tree->children->size(tree->children);

		for	(i = 0; i < n; i++)
		{   
			t   = (pANTLR3_BASE_TREE) tree->children->get(tree->children, i);

			if  (i > 0)
			{
				string->append8(string, " ");
			}
			string->appendS(string, t->toStringTree(t));
		}
	}
	if	(tree->isNilNode(tree) == ANTLR3_FALSE)
	{
		string->append8(string,")");
	}

	return  string;
}
开发者ID:10114395,项目名称:android-5.0.0_r5,代码行数:45,代码来源:antlr3basetree.c

示例12: dbgAddChild

static	void	
dbgAddChild (pANTLR3_BASE_TREE_ADAPTOR adaptor, pANTLR3_BASE_TREE t, pANTLR3_BASE_TREE child)
{
	if	(t != NULL && child != NULL)
	{
		t->addChild(t, child);
		adaptor->debugger->addChild(adaptor->debugger, t, child);
	}
}
开发者ID:Daniel1892,项目名称:tora,代码行数:9,代码来源:antlr3basetreeadaptor.c

示例13:

static	void					
replaceChildren
(pANTLR3_BASE_TREE_ADAPTOR adaptor, pANTLR3_BASE_TREE parent, ANTLR3_INT32 startChildIndex, ANTLR3_INT32 stopChildIndex, pANTLR3_BASE_TREE t)
{
	if	(parent != NULL)
	{
		parent->replaceChildren(parent, startChildIndex, stopChildIndex, t);
	}
}
开发者ID:jariba,项目名称:europa-pso,代码行数:9,代码来源:antlr3commontreeadaptor.c

示例14: if

static ANTLR3_UINT32	    getCharPositionInLine	(pANTLR3_BASE_TREE tree)
{
	pANTLR3_COMMON_TOKEN    token;

	token   = ((pANTLR3_COMMON_TREE)(tree->super))->token;

	if	(token == NULL || token->getCharPositionInLine(token) == -1)
	{
		if  (tree->getChildCount(tree) > 0)
		{
			pANTLR3_BASE_TREE	child;

			child   = (pANTLR3_BASE_TREE)tree->getChild(tree, 0);

			return child->getCharPositionInLine(child);
		}
		return 0;
	}
	return  token->getCharPositionInLine(token);
}
开发者ID:166MMX,项目名称:antlr3,代码行数:20,代码来源:antlr3commontree.c

示例15:

	ASTNode::ASTNode(const pANTLR3_BASE_TREE node)
	{
		m_LineNumber = node->getLine(node);
		m_CharPosition = node->getCharPositionInLine(node);

		pANTLR3_BASE_TREE n = node;
		while ((n != NULL) && (n->u == NULL))
		{ 
			if (n->u != NULL)
			{
				m_FileName = (wchar_t*) n->u;
				node->u = n->u;
				break;
			}
			else
			{
				n = n->getParent(n);
			}
		}
	}
开发者ID:ernestobad,项目名称:ContainedObjects,代码行数:20,代码来源:ASTNode.cpp


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