本文整理汇总了C++中float2::dot方法的典型用法代码示例。如果您正苦于以下问题：C++ float2::dot方法的具体用法？C++ float2::dot怎么用？C++ float2::dot使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类float2的用法示例。
在下文中一共展示了float2::dot方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: PolyShapeValueOnAxis
static inline float PolyShapeValueOnAxis(SimBody *poly, const float2 n, const float d)
{
vector<float2> &verts = poly->transformedVertices;
float minft = n.dot(verts[0]);
for(u32 i=1;i<verts.size();++i)
{
minft = min(minft, n.dot(verts[i]));
}
return minft - d;
};示例2: SATCollide
bool SATCollide(SimBody *body1, SimBody *body2, float2 &N, f32 &t)
{
SimBody &a = *body1;
SimBody &b = *body2;
if(a.vertices.size() < 2 && b.vertices.size() < 2) return false;
Mat22 OA = Mat22::RotationMatrix(a.rotation_in_rads);
Mat22 OB = Mat22::RotationMatrix(b.rotation_in_rads);
Mat22 OB_T = OB.Transpose();
Mat22 xOrient = OA * OB_T;
float2 xOffset = (a.position - b.position) * OB_T;
const u32 MAX_SEPERATING_AXIS = 16;
float2 xAxis[MAX_SEPERATING_AXIS];
f32 taxis[MAX_SEPERATING_AXIS];
u32 axisCount = 0;
for(u32 i=0;i<a.seperatingAxis.size();++i)
{
xAxis[axisCount] = a.seperatingAxis[i] * xOrient;
if(!IntervalIntersect(a.vertices, b.vertices, xAxis[axisCount],
xOffset, xOrient, taxis[axisCount], t))
{
return false;
}
++axisCount;
};
for(u32 i=0;i<b.seperatingAxis.size();++i)
{
xAxis[axisCount] = b.seperatingAxis[i];
if(!IntervalIntersect(a.vertices, b.vertices, xAxis[axisCount],
xOffset, xOrient, taxis[axisCount], t))
{
return false;
}
++axisCount;
};
if(!GetMinimumTranslationVector(xAxis, taxis, axisCount, N, t))
{
return false;
}
f32 D = N.dot(xOffset);
N = D < 0.0f ? -N : N;
N = N * OB;
return true;
};示例3: IntervalIntersect
bool IntervalIntersect(const std::vector<float2> &aVertices,
const std::vector<float2> &bVertices, const float2 &axis, const float2 &relPos,
const Mat22 &xOrient, f32 &taxis, f32 tmax)
{
SATProjection proj0 = GetInterval(aVertices, axis * xOrient.Transpose());
SATProjection proj1 = GetInterval(bVertices, axis);
f32 h = relPos.dot(axis);
proj0.min += h;
proj0.max += h;
f32 d0 = proj0.min - proj1.max;
f32 d1 = proj1.min - proj0.max;
if(d0 > 0.0f || d1 > 0.0f)
{
return false;
}
taxis = d0 > d1 ? d0 : d1;
return true;
};示例4:
inline const float operator *(const float2& a, const float2& b)
{
return a.dot(b);
}