本文整理汇总了C++中docstring::substr方法的典型用法代码示例。如果您正苦于以下问题：C++ docstring::substr方法的具体用法？C++ docstring::substr怎么用？C++ docstring::substr使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类docstring的用法示例。
在下文中一共展示了docstring::substr方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: path_prefix_is
bool path_prefix_is(string & path, string const & pre, path_case how)
{
#ifdef __APPLE__
docstring const p1 = from_utf8(path);
docstring const p2 = from_utf8(pre);
docstring::size_type const p1_len = p1.length();
docstring::size_type const p2_len = p2.length();
docstring::size_type common_len = common_path(p1, p2);
if (p2[p2_len - 1] == '/' && p1_len != p2_len)
++common_len;
if (common_len != p2_len)
return false;
if (how == CASE_ADJUSTED && !prefixIs(path, pre)) {
if (p1_len < common_len)
path = to_utf8(p2.substr(0, p1_len));
else
path = to_utf8(p2 + p1.substr(common_len,
p1_len - common_len));
}
return true;
#else
// silence compiler warnings
(void)how;
return prefixIs(path, pre);
#endif
}示例2: add
bool BranchList::add(docstring const & s)
{
bool added = false;
size_t i = 0;
while (true) {
size_t const j = s.find_first_of(separator_, i);
docstring name;
if (j == docstring::npos)
name = s.substr(i);
else
name = s.substr(i, j - i);
// Is this name already in the list?
bool const already =
find_if(list.begin(), list.end(),
BranchNamesEqual(name)) != list.end();
if (!already) {
added = true;
Branch br;
br.setBranch(name);
br.setSelected(false);
br.setFileNameSuffix(false);
list.push_back(br);
}
if (j == docstring::npos)
break;
i = j + 1;
}
return added;
}示例3: signedWidth
int GuiFontMetrics::signedWidth(docstring const & s) const
{
if (s.empty())
return 0;
if (s[0] == '-')
return -width(s.substr(1, s.size() - 1));
else
return width(s);
}示例4: add
bool IndicesList::add(docstring const & n, docstring const & s)
{
bool added = false;
size_t i = 0;
while (true) {
size_t const j = n.find_first_of(separator_, i);
docstring name;
if (j == docstring::npos)
name = n.substr(i);
else
name = n.substr(i, j - i);
// Is this name already in the list?
bool const already =
find_if(list.begin(), list.end(),
IndexNamesEqual(name)) != list.end();
if (!already) {
added = true;
Index in;
in.setIndex(name);
docstring sc = s.empty() ?
trim(lowercase(name.substr(0, 3))) : s;
if (findShortcut(sc) != 0) {
int i = 1;
docstring scn = sc + convert<docstring>(i);
while (findShortcut(scn) != 0) {
++i;
scn = sc + convert<docstring>(i);
}
in.setShortcut(scn);
} else
in.setShortcut(sc);
list.push_back(in);
}
if (j == docstring::npos)
break;
i = j + 1;
}
return added;
}