本文整理汇总了C++中docstring::find_first_of方法的典型用法代码示例。如果您正苦于以下问题：C++ docstring::find_first_of方法的具体用法？C++ docstring::find_first_of怎么用？C++ docstring::find_first_of使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类docstring的用法示例。
在下文中一共展示了docstring::find_first_of方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: validate
QValidator::State PathValidator::validate(QString & qtext, int &) const
{
if (!latex_doc_)
return QValidator::Acceptable;
docstring const text = support::trim(qstring_to_ucs4(qtext));
if (text.empty())
return acceptable_if_empty_ ?
QValidator::Acceptable : QValidator::Intermediate;
docstring invalid_chars = from_ascii("#$%{}()[]\"^");
if (!tex_allows_spaces_)
invalid_chars += ' ';
if (text.find_first_of(invalid_chars) != docstring::npos) {
static int counter = 0;
if (counter == 0) {
Alert::error(_("Invalid filename"),
_("LyX does not provide LaTeX support for file names containing any of these characters:\n") +
printable_list(invalid_chars));
}
++counter;
return QValidator::Intermediate;
}
return QValidator::Acceptable;
}示例2: add
bool BranchList::add(docstring const & s)
{
bool added = false;
size_t i = 0;
while (true) {
size_t const j = s.find_first_of(separator_, i);
docstring name;
if (j == docstring::npos)
name = s.substr(i);
else
name = s.substr(i, j - i);
// Is this name already in the list?
bool const already =
find_if(list.begin(), list.end(),
BranchNamesEqual(name)) != list.end();
if (!already) {
added = true;
Branch br;
br.setBranch(name);
br.setSelected(false);
br.setFileNameSuffix(false);
list.push_back(br);
}
if (j == docstring::npos)
break;
i = j + 1;
}
return added;
}示例3: add
bool IndicesList::add(docstring const & n, docstring const & s)
{
bool added = false;
size_t i = 0;
while (true) {
size_t const j = n.find_first_of(separator_, i);
docstring name;
if (j == docstring::npos)
name = n.substr(i);
else
name = n.substr(i, j - i);
// Is this name already in the list?
bool const already =
find_if(list.begin(), list.end(),
IndexNamesEqual(name)) != list.end();
if (!already) {
added = true;
Index in;
in.setIndex(name);
docstring sc = s.empty() ?
trim(lowercase(name.substr(0, 3))) : s;
if (findShortcut(sc) != 0) {
int i = 1;
docstring scn = sc + convert<docstring>(i);
while (findShortcut(scn) != 0) {
++i;
scn = sc + convert<docstring>(i);
}
in.setShortcut(scn);
} else
in.setShortcut(sc);
list.push_back(in);
}
if (j == docstring::npos)
break;
i = j + 1;
}
return added;
}