本文整理汇总了C++中btMatrix3x3::solve33方法的典型用法代码示例。如果您正苦于以下问题：C++ btMatrix3x3::solve33方法的具体用法？C++ btMatrix3x3::solve33怎么用？C++ btMatrix3x3::solve33使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类btMatrix3x3的用法示例。
在下文中一共展示了btMatrix3x3::solve33方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: computeGyroscopicImpulseImplicit_World
btVector3 btRigidBody::computeGyroscopicImpulseImplicit_World(btScalar step) const
{
// use full newton-euler equations. common practice to drop the wxIw term. want it for better tumbling behavior.
// calculate using implicit euler step so it's stable.
const btVector3 inertiaLocal = getLocalInertia();
const btVector3 w0 = getAngularVelocity();
btMatrix3x3 I;
I = m_worldTransform.getBasis().scaled(inertiaLocal) *
m_worldTransform.getBasis().transpose();
// use newtons method to find implicit solution for new angular velocity (w')
// f(w') = -(T*step + Iw) + Iw' + w' + w'xIw'*step = 0
// df/dw' = I + 1xIw'*step + w'xI*step
btVector3 w1 = w0;
// one step of newton's method
{
const btVector3 fw = evalEulerEqn(w1, w0, btVector3(0, 0, 0), step, I);
const btMatrix3x3 dfw = evalEulerEqnDeriv(w1, w0, step, I);
btVector3 dw;
dw = dfw.solve33(fw);
//const btMatrix3x3 dfw_inv = dfw.inverse();
//dw = dfw_inv*fw;
w1 -= dw;
}
btVector3 gf = (w1 - w0);
return gf;
}