本文整理汇总了C++中box::bisect_at方法的典型用法代码示例。如果您正苦于以下问题：C++ box::bisect_at方法的具体用法？C++ box::bisect_at怎么用？C++ box::bisect_at使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类box的用法示例。
在下文中一共展示了box::bisect_at方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: solve
box naive_icp::solve(box b, contractor & ctc,
scoped_vec<shared_ptr<constraint>> const & ctrs,
SMTConfig & config, BranchHeuristic& brancher) {
thread_local static unordered_set<shared_ptr<constraint>> used_constraints;
used_constraints.clear();
thread_local static vector<box> solns;
thread_local static vector<box> box_stack;
solns.clear();
box_stack.clear();
box_stack.push_back(b);
do {
DREAL_LOG_INFO << "naive_icp::solve - loop"
<< "\t" << "box stack Size = " << box_stack.size();
b = box_stack.back();
box_stack.pop_back();
prune(b, ctc, config, used_constraints);
if (!b.is_empty()) {
if (config.nra_use_stat) { config.nra_stat.increase_branch(); }
vector<int> sorted_dims = brancher.sort_branches(b, ctrs, config);
if (sorted_dims.size() > 0) {
int const i = sorted_dims[0];
tuple<int, box, box> splits = b.bisect_at(sorted_dims[0]);
box const & first = get<1>(splits);
box const & second = get<2>(splits);
assert(first.get_idx_last_branched() == i);
assert(second.get_idx_last_branched() == i);
if (second.is_bisectable()) {
box_stack.push_back(second);
box_stack.push_back(first);
} else {
box_stack.push_back(first);
box_stack.push_back(second);
}
if (config.nra_proof) {
config.nra_proof_out << "[branched on "
<< b.get_name(i)
<< "]" << endl;
}
} else {
config.nra_found_soln++;
if (config.nra_multiple_soln > 1) {
// If --multiple_soln is used
output_solution(b, config, config.nra_found_soln);
}
if (config.nra_found_soln >= config.nra_multiple_soln) {
break;
}
solns.push_back(b);
}
}
} while (box_stack.size() > 0);
ctc.set_used_constraints(used_constraints);
if (config.nra_multiple_soln > 1 && solns.size() > 0) {
return solns.back();
} else {
assert(!b.is_empty() || box_stack.size() == 0);
return b;
}
}