本文整理汇总了C++中TreeNode::begin方法的典型用法代码示例。如果您正苦于以下问题：C++ TreeNode::begin方法的具体用法？C++ TreeNode::begin怎么用？C++ TreeNode::begin使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类TreeNode的用法示例。
在下文中一共展示了TreeNode::begin方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: while
SCORE_LIB_STATE_EXPORT
bool operator==(
const TreeNode<State::ExprData>& lhs,
const TreeNode<State::ExprData>& rhs)
{
const auto& ltd = static_cast<const State::ExprData&>(lhs);
const auto& rtd = static_cast<const State::ExprData&>(rhs);
bool b = (ltd == rtd) && (lhs.m_children.size() == rhs.m_children.size());
if (!b)
return false;
auto l = lhs.begin();
auto e = lhs.end();
auto r = rhs.begin();
while (l != e)
{
if (*l != *r)
return false;
++l;
++r;
}
return true;
}示例2: __run__
void PreRootVisitor::__run__ (const TreeNode &node)
{
process(node);
TreeNode::ChildrenIterator it = node.begin ();
while(it != node.end())
{
__run__(*it);
it ++;
}
}示例3: insert
iterator insert(StoredObject&& toStore)
{
TreeNode* node = getNode(toStore.location);
if (node->level() > 0)
{
// We store one element at time so there will be a moment before node overflow when its
// count will be equal capacity. Then we'll relocate all its elements to the new child
// nodes. At worst scenario, all elements will be relocated to the same node, so its
// count() will be again equal to capacity. The loop ends when at least one element is
// relocated to the another child node.
while (node->count() == nodeCapacity && node->level() > 0)
{
typename TreeNode::iterator it;
typename TreeNode::iterator itEnd = node->end();
for (it = node->begin(); it != itEnd; ++it)
{
node->child(it->location).insert(std::move(*it));
}
node->clear();
node = &(node->child(toStore.location));
}
}
return iterator(node, node->insert(std::move(toStore)));
}