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C++ Sequence::back方法代码示例

本文整理汇总了C++中Sequence::back方法的典型用法代码示例。如果您正苦于以下问题:C++ Sequence::back方法的具体用法?C++ Sequence::back怎么用?C++ Sequence::back使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Sequence的用法示例。


在下文中一共展示了Sequence::back方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: stitch

void Path::stitch(Sequence::iterator first_replaced,
                  Sequence::iterator last_replaced,
                  Sequence &source)
{
  if (!source.empty()) {
    if ( first_replaced != get_curves().begin() ) {
      if ( (*first_replaced)->initialPoint() != source.front()->initialPoint() ) {
        Curve *stitch = new StitchSegment((*first_replaced)->initialPoint(),
                                          source.front()->initialPoint());
        source.insert(source.begin(), boost::shared_ptr<Curve>(stitch));
      }
    }
    if ( last_replaced != (get_curves().end()-1) ) {
      if ( (*last_replaced)->finalPoint() != source.back()->finalPoint() ) {
        Curve *stitch = new StitchSegment(source.back()->finalPoint(),
                                          (*last_replaced)->finalPoint());
        source.insert(source.end(), boost::shared_ptr<Curve>(stitch));
      }
    }
  } else if ( first_replaced != last_replaced && first_replaced != get_curves().begin() && last_replaced != get_curves().end()-1) {
    if ( (*first_replaced)->initialPoint() != (*(last_replaced-1))->finalPoint() ) {
      Curve *stitch = new StitchSegment((*(last_replaced-1))->finalPoint(),
                                        (*first_replaced)->initialPoint());
      source.insert(source.begin(), boost::shared_ptr<Curve>(stitch));
    }
  }
}
开发者ID:Spin0za,项目名称:inkscape,代码行数:27,代码来源:path.cpp

示例2: getPercentile

double DeterminatorInterpolated::getPercentile(const Sequence &sequence, int percentile) const {
    size_t size = sequence.size();
    double coeff = 100.0 / size;

    double calcIdx = percentile / coeff - .5;

    if (calcIdx <= 0) return sequence.front();
    if (calcIdx >= size - 1) return sequence.back();

    size_t idx0 = (size_t) floor(calcIdx);
    int v0 = sequence.at(idx0);
    int v1 = sequence.at(idx0 + 1);

    double p0 = 100.0 / size * (idx0);

    double slope = size / 100.0 * (percentile - p0);

    return v0 + (v1 - v0) * slope;
}
开发者ID:antifriz,项目名称:ooup,代码行数:19,代码来源:determinator_interpolated.cpp


注:本文中的Sequence::back方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。