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C++ Puzzle::nextSlot方法代码示例

本文整理汇总了C++中Puzzle::nextSlot方法的典型用法代码示例。如果您正苦于以下问题:C++ Puzzle::nextSlot方法的具体用法?C++ Puzzle::nextSlot怎么用?C++ Puzzle::nextSlot使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Puzzle的用法示例。


在下文中一共展示了Puzzle::nextSlot方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: main

int main(int argc, char *argv[]) {
  // timer
  struct timeval start, end;
  long mtime, seconds, useconds;    
  gettimeofday(&start, NULL);

  time_t startTime = time(0);

  if (argc != 3) {
    printf("wrong number of inputs\n");
    exit(1);
  }

  int** grid = fileTo2dArray(argv[1], atoi(argv[2]));
  Puzzle p = Puzzle(grid, atoi(argv[2]));
  p.initialize();

  /*  
  p->printGridDim();
  p->printGrid();
  p->printPreassigned();
  p->printInitCandidates();
  
  printf("start: %i, %i\n", p->getCurrentRow(), p->getCurrentCol());
  while (p->nextSlot()) {
    printf("nextslot: row is %i, col is %i\n", p->getCurrentRow(), p->getCurrentCol());
  }
  
  while (p->prevSlot()) {
    printf("prevslot: row is %i, col is %i\n", p->getCurrentRow(), p->getCurrentCol());
  }
  

  printf("TEST: check candidates\n");
  p->checkCandidates(p->getCurrentRow(), p->getCurrentCol());
  printf("TEST: assign\n");
  p->assign(p->getCurrentRow(), p->getCurrentCol());
  printf("TEST: update neighbors\n");
  p->updateNeighborConflicts(p->getCurrentRow(), p->getCurrentCol(), p->getCurrentAssigned(0, 0), true);
  printf("TEST: check neighbors\n");
  p->checkNeighborCandidates(p->getCurrentRow(), p->getCurrentCol());
  */

  //int counter=10000;  
  while (!p.isSolved()) {
  //while (!p->isSolved() && counter>0) {
    //counter--;
    if (testLevel > 0) printf("step 1: on (%i, %i)\n", p.getCurrentRow(), p.getCurrentCol());
    //printf("step 1: current row %i, current col %i, %i\n", p->getCurrentRow(), p->getCurrentCol(), p->getCurrentAssigned(p->getCurrentRow(), p->getCurrentCol()));
    bool hasCandidate = p.checkCandidates(p.getCurrentRow(), p.getCurrentCol(), false);
    //printf("step 1\n");
    // step 1
    if (hasCandidate) {
      //printf("step 3\n");
      // step 3
      bool succeeded;
      if (p.assign(p.getCurrentRow(), p.getCurrentCol())) {
        if (testLevel > 0) 
          printf("step 3: on (%i, %i), assigned %i\n", p.getCurrentRow(), p.getCurrentCol(), p.getCurrentAssigned(p.getCurrentRow(), p.getCurrentCol()));
        //printf("step 3: assignment succeeded\n");
        //printf("calling updateNeighborConflicts with %i, %i, %i\n", p->getCurrentRow(), p->getCurrentCol(), p->getCurrentAssigned(p->getCurrentRow(), p->getCurrentCol()));
        //printf("pre-assign candidate list: \n"); 
        //p->printInitCandidates();
        // deprecated
        //p->updateNeighborConflicts(p->getCurrentRow(), p->getCurrentCol(), p->getCurrentAssigned(p->getCurrentRow(), p->getCurrentCol()), true);
        //printf("post-assign candidate list: \n"); 
        //p->printInitCandidates();    
        //printf("step 3: updateNeighborConflicts succeeded\n");
        succeeded = p.checkNeighborAssignments(p.getCurrentRow(), p.getCurrentCol());
      }
      else {
        printf("error: reached slot with no candidates. shouldn't happen. exiting.\n");
        exit(1);
      }

      if (succeeded) {
        //printf("step 5\n");
        // step 5
        if (testLevel > 0) printf("step 5: next slot\n");
        p.nextSlot();
        p.copyCandidates(p.getCurrentRow(), p.getCurrentCol());
      }
      else {
        //printf("step 4\n");
        // step 4
        if (testLevel > 0) 
          printf("step 4: on (%i, %i), unassigning %i\n", p.getCurrentRow(), p.getCurrentCol(), p.getCurrentAssigned(p.getCurrentRow(), p.getCurrentCol()));
        //printf("pre-update candidate list: \n"); 
        //p.printInitCandidates();
        //deprecated
        //p->updateNeighborConflicts(p->getCurrentRow(), p->getCurrentCol(), p->getCurrentAssigned(p->getCurrentRow(), p->getCurrentCol()), false);
        //printf("post-update candidate list: \n"); 
        //p->printInitCandidates();
        p.removeAndInvalidate(p.getCurrentRow(), p.getCurrentCol());
        // loops back to front
      }
    }
    else {
      //printf("step 2\n");
      // step 2
//.........这里部分代码省略.........
开发者ID:haotianwang,项目名称:cs194_proj,代码行数:101,代码来源:candidate_vector_sudoku_solver.cpp


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